The radius of a nucleus of hydrogen is approximately
, while we can use the Borh radius as the distance of an electron from the nucleus in a hydrogen atom:
The radius of a dime is approximately
: if we assume that the radius of the nucleus is exactly this value, then we can find how far is the electron by using the proportion
from which we find
So, if the nucleus had the size of a dime, we would find the electron approximately 500 meters away.
1. If Maggie gives her cat an unfair advantage, her experimental results will be biased.
Explanation:
Maggie using her cat in the experiment to test for intelligence gives the cat an unfair advantage, her experimental results will be biased.
- Due to her emotional attachment with the cat, the experimental results will be skewed to portraying her cat as intelligence.
- This is not a good experiment to carry out.
- Such an experiment should be carried out with an unknown cat.
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Experiment brainly.com/question/1621519
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Answer:
C) The function F(x) for 0 < x < 5, the block's initial velocity, and the value of Fr.
Explanation:
Yo want to prove the following equation:
That is, the net force exerted on an object is equal to the change in the kinetic energy of the object.
The previous equation is also equal to:
(1)
m: mass of the block
vf: final velocity
v_o: initial velocity
Ff: friction force
F(x): Force
x: distance
You know the values of vf, m and x.
In order to prove the equation (1) it is necessary that you have C The function F(x) for 0 < x < 5, the block's initial velocity, and the value of F. Thus you can calculate experimentally both sides of the equation.
Momentum = (mass) x (speed)
= (0.4 kg) x (45 m/s)
= 18 kg-m/s in the direction from the mound to the plate.
Answer:
t = 0.657 s
Explanation:
given,
initial vertical velocity = 7.5 m/s
initial horizontal velocity = 0 m/s
angle = 49◦
using kinetic equation
final velocity in vertical direction
v sinθ = u_y - gt ........................(1)
final velocity in horizontal direction
v cosθ = u_x + a_x × t
here u_x = 0.0 m/s
v cosθ = a_x×t ......................(2)
Dividing equation (1) / (2)
solving for time t
u_y = initial velocity along x direction
acceleration along a_x = 1.4 m/s²
g = acceleration due to gravity = 9.8 m/s²
θ = 43° , u_y = 7.5 m/s
t = 0.657 s
time taken by the particle is t = 0.657 s
