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inessss [21]
2 years ago
9

Normally light waves move in all different directions. When light becomes P________, all of the electric fields in the waves mov

e parallel to each other
I'm looking for a 9 letter word that starts with P! I really can't find the answer and I've been searching through my physics book.
Physics
2 answers:
mezya [45]2 years ago
6 0

Answer:

Here to help, I am most positive that the answer it polarized.

Explanation:

here is the definition in case you are skeptical

Polarization: the action of restricting the vibrations of a transverse wave, especially light, wholly or partially to one direction.

the word also happens to be 9 letters long.

mark me brainliest if this helped.

Aloiza [94]2 years ago
4 0

Answer:im so sorry i cant find anything either ask your teacher for some help is the best thing i can do

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A proton having an initial velvocity of 20.0i Mm/s enters a uniform magnetic field of magnitude 0.300 T with a direction perpend
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The time interval for which the proton remains in the field is -

Δt = $\frac{\pi R}{40}.

We have a proton entering a uniform magnetic field which is in a direction perpendicular to the proton's velocity.

We have to determine time interval during which the proton is in the field.

<h3>What is the magnitude of force on the charged particle moving in a uniform magnetic field?</h3>

The magnitude of force on the charged particle moving in a uniform magnetic field is given by -

F = qvB sinθ



According to the question, we have -

Entering Velocity (v) = 20 i  m/s

Magnetic field intensity (B) = 0.3 T

Leaving velocity (u) = - 20 j  m/s

Now -

The entering and leaving velocity vectors have 90 degrees difference between them. Therefore, only a quarter of distance of the complete circular path of radius 'R' is traced by the proton. Therefore -

d = $\frac{2\pi r}{4} = $\frac{\pi R}{2}

Since, the radius of circular path is not given, we will assume it R.

Therefore, time for which proton remained in the field is -

t = $\frac{\pi R}{2v} = \frac{\pi R}{40}

Hence, the time interval for which the proton remains in the field is -

Δt = $\frac{\pi R}{40}

To solve more questions on Force on charged particle, visit the link below-

brainly.com/question/14597200

#SPJ4



 



6 0
1 year ago
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