Heat flux (i) = k.a.temp variation/d
i = 250 J/s or 250w ; d = 2.1 x 10^-3m ; A = 1.9m^2 ; K (Body Fat) = 0.2W/m.Kelvin ; Temp. Var. (Delta T) = ?
-> 250 = 0.2 x 1.9 x deltaT/2.1 x 10^-3
-> 250 x 2.1 x 10^-3 = 0.38 x deltaT
-> 525 x 10^-3 = 38x10^-2 x deltaT
-> deltaT = 525 x 10^-3/ 38 x 10^-2
-> deltaT = 13.81 x 10^(-3 - (-2))
-> deltaT = 13.81 x 10^-1
-> deltaT = 1.381 K
Ke= 1/2 x m x v^2
Ke= 1/2 x 2.1 x 30^2
Energy = 945 J
Answer:
60 watts
Explanation:
Given that
Mass of the animal, m = 5 kg
Velocity of the animal, v = 10 m/s
Distance moved by the animal, d = 10 m
Drag force, F(d) = 12 N
Time taken, t = 2 seconds
To start with, we need to find the power output in itself before proceeding to find the average power output. And as such, we have
Power = Force * Distance/Time
But Distance/Time is velocity, so
Power = Force * Velocity
Power = 12 * 10
Power = 120 W.
We then use this power gotten to find the average power output.
Power(avg) = P/t
Power(avg) = 120 / 2
Power(avg) = 60 Watts.
Therefore, the average power output is found to be 60 Watts
Answer:
Explanation:
As we know that charge is always conserved
so here we have
initial total charge = final total charge
also we know that gamma rays are chargeless and massless particles
so we have
charge on deuterium is given as
Q = charge on proton + charge on neutron - charge on gamma
so we have
