Answer:
The magnitude of the acceleration of the tip of the minute hand of the clock
.
Explanation:
Given that,
Length of minute hand = 0.55 m
Length of hour hand = 0.26 m
The time taken by the minute hand to complete one revelation is

We need to calculate the angular frequency
Using formula of angular frequency

Put the value into the formula


We need to calculate the magnitude of the acceleration of the tip of the minute hand of the clock
Using formula of acceleration

Put the value into the formula


Hence, The magnitude of the acceleration of the tip of the minute hand of the clock
.
The value of the force, F₀, at equilibrium is equal to the horizontal
component of the tension in string 2.
Response:
- The value of F₀ so that string 1 remains vertical is approximately <u>0.377·M·g</u>
<h3>How can the equilibrium of forces be used to find the value of F₀?</h3>
Given:
The weight of the rod = The sum of the vertical forces in the strings
Therefore;
M·g = T₂·cos(37°) + T₁
The weight of the rod is at the middle.
Taking moment about point (2) gives;
M·g × L = T₁ × 2·L
Therefore;

Which gives;


F₀ = T₂·sin(37°)
Which gives;

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Learn more about equilibrium of forces here:
brainly.com/question/6995192
Solution :
Given data is :
Density of the milk in the tank, 
Length of the tank, x = 9 m
Height of the tank, z = 3 m
Acceleration of the tank, 
Therefore, the pressure difference between the two points is given by :

Since the tank is completely filled with milk, the vertical acceleration is 

Therefore substituting, we get




Therefore the maximum pressure difference in the tank is Δp = 47.87 kPa and is located at the bottom of the tank.
Answer:
b. Both stars will have the same shift.
Explanation:
It's a very simple problem to solve. Star 1 is approaching toward Earth with a speed v, so let's assume that the change in Doppler Shift is +F and Star 2 is moving away so the change in Doppler shift is -F. But it's time to notice the speed of both stars and that is same but only directions are different. speed is the main factor here. The magnitude of both shifts is F as we can see and + and - are showing there direction of motion. So, because of same amount of speed, both stars will have same shift magnitude. (Just the directions are different)