Molar mass Na₂SO₄. 10H₂O = 322.19 g/mol
Molar mass H₂O = 18.0
% Element = molar mass / total mass x 100
% Element = 18 / 322,19 x 100
% Element = 5.59 %
Answer A
hope this helps!
There is no question on here lol
Answer:
9.80 g
Explanation:
The molecular mass of the atoms mentioned in the question is as follows -
S = 32 g / mol
F = 19 g / mol
The molecular mass of the compound , SF₆ = 32 + ( 6 * 19 ) = 146 g / mol
The mass of 6 F = 6 * 19 = 114 g /mol .
The percentage of F in the compound =
mass of 6 F / total mass of the compound * 100
Hence ,
The percentage of F in the compound = 114 g /mol / 146 g / mol * 100
78.08 %
Hence , from the question ,
In 12.56 g of the compound ,
The grams of F = 0.7808 * 12.56 = 9.80 g
I believe it is C, as helium is one of the lightest noble gases making the particles move faster.
