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Ostrovityanka [42]
3 years ago
5

If you have 0.56 moles of an ideal gas at 87 ° C and a pressure of 569 torr, what volume will the gas take up?

Chemistry
2 answers:
xxTIMURxx [149]3 years ago
4 0
The ideal gas law: PV = nRT

Conversions: 
87°C = 360K
P = 0.75 atm
R = 0.0821
n = 0.56

0.75V = (0.56)(0.0821)(360)

V = 22 L
NikAS [45]3 years ago
4 0

Explanation:

The given data is as follows.

            n = 0.56 moles,              T = 87^{o}C = (87 + 273) K = 360 K

            P = 569 torr = 0.748 atm (as 1 torr = 0.0013 atm)

According to ideal gas equation, PV = nRT

Therefore, putting given values into the above formula as follows.

                           PV = nRT

     0.748 \times V = 0.56 \times 0.0821 L atm/mol K \times 360 K

                     V = 22.12 L

Thus, we can conclude that the given gas will take up 22.12 L of volume.

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By stoichiometry of the reaction, the following amounts of moles participate in the reaction:

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