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mote1985 [20]
3 years ago
6

How many molecules of glucose are present in 1273 g. CaHlz0s?

Chemistry
1 answer:
Vinil7 [7]3 years ago
3 0

Answer : The number of glucose molecule are, 42.55\times 10^{23}

Explanation : Given,

Mass of C_6H_{12}O_6 = 1273 g

Molar mass of C_6H_{12}O_6 = 180.156 g/mole

First we have to calculate the moles of C_6H_{12}O_6.

\text{Moles of }C_6H_{12}O_6=\frac{\text{Mass of }C_6H_{12}O_6}{\text{Molar mass of }C_6H_{12}O_6}=\frac{1273g}{180.156g/mole}=7.066moles

Now we have to calculate the number of molecules of glucose.

As, 1 mole of glucose contains 6.022\times 10^{23} number of glucose molecules

So, 7.066 mole of glucose contains 7.066\times 6.022\times 10^{23}=42.55\times 10^{23} number of glucose molecules

Hence, the number of glucose molecule are, 42.55\times 10^{23}

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Boron has an average mass of 10.81. One isotope of boron has a mass of 10.012938 and a relative abundance of 19.80 percent. The
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The average mass of an atom is calculated with the formula:

average mass = abundance of isotope (1) × mass of isotope (1) + abundance of isotope (2) × mass of isotope (2) + ...  an so on

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average mass of boron = abundance of isotope (1) × mass of isotope (1) + abundance of isotope (2) × mass of isotope (2)

We plug in the values:

10.81 = 0.1980 × 10.012938  + 0.8020 × mass of isotope (2)

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Which reaction is a decomposition reaction? A. 2KClO3 → 2KCl + 3O2 B. 4Na + O2 → 2Na2O C. ZnS + 3O2 → 2ZnO + 2SO2 D. 2NaBr + CaF
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The given reactions are:

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