Question

How many molecules of glucose are present in 1273 g. CaHlz0s?

Answer 1

Answer : The number of glucose molecule are, $42.55\times 10^{23}$

Explanation : Given,

Mass of $C_6H_{12}O_6$ = 1273 g

Molar mass of $C_6H_{12}O_6$ = 180.156 g/mole

First we have to calculate the moles of $C_6H_{12}O_6$.

$\text{Moles of }C_6H_{12}O_6=\frac{\text{Mass of }C_6H_{12}O_6}{\text{Molar mass of }C_6H_{12}O_6}=\frac{1273g}{180.156g/mole}=7.066moles$

Now we have to calculate the number of molecules of glucose.

As, 1 mole of glucose contains $6.022\times 10^{23}$ number of glucose molecules

So, 7.066 mole of glucose contains $7.066\times 6.022\times 10^{23}=42.55\times 10^{23}$ number of glucose molecules

Hence, the number of glucose molecule are, $42.55\times 10^{23}$