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mote1985 [20]
2 years ago
6

How many molecules of glucose are present in 1273 g. CaHlz0s?

Chemistry
1 answer:
Vinil7 [7]2 years ago
3 0

Answer : The number of glucose molecule are, 42.55\times 10^{23}

Explanation : Given,

Mass of C_6H_{12}O_6 = 1273 g

Molar mass of C_6H_{12}O_6 = 180.156 g/mole

First we have to calculate the moles of C_6H_{12}O_6.

\text{Moles of }C_6H_{12}O_6=\frac{\text{Mass of }C_6H_{12}O_6}{\text{Molar mass of }C_6H_{12}O_6}=\frac{1273g}{180.156g/mole}=7.066moles

Now we have to calculate the number of molecules of glucose.

As, 1 mole of glucose contains 6.022\times 10^{23} number of glucose molecules

So, 7.066 mole of glucose contains 7.066\times 6.022\times 10^{23}=42.55\times 10^{23} number of glucose molecules

Hence, the number of glucose molecule are, 42.55\times 10^{23}

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Rudiy27
Let us assume that the ring is a size 7 ring, which has a circumference of 54.3 millimeters. Converting this to centimeters, the circumference of the ring is:

54.3 mm = 5.43 cm

Now, we determine the number of gold atoms that will be present in this:

5.43 / 1 x 10⁻⁹

There will be 5.43 x 10⁹ atoms


We now determine the number of moles this is by:

one mole = 6.02 x 10²³ atoms

Moles = 5.43 x 10⁹ / 6.02 x 10²³ 
Moles = 9.01 x 10⁻¹⁵ moles

The molar mass of gold is 197 g/mol

The mass is 9.01 x 10⁻¹⁵  * 197

The mass of the strand is 1.76 x 10⁻¹² grams
8 0
3 years ago
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How many moles are in 65 g of carbon dioxide (CO2)?
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The answer is 44.0095. We assume you are converting between grams CO2 and mole.
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Question 8
nexus9112 [7]
72 degrees C (minus 273)
6 0
3 years ago
A 48.0g sample of quartz, which has a specific heat capacity of 0.730·J·g−1°C−1, is dropped into an insulated container containi
Butoxors [25]

Answer:

The equilibrium temperature of the water is 26.7 °C

Explanation:

<u>Step 1:</u> Data given

Mass of the sample quartz = 48.0 grams

Specific heat capacity of the sample = 0.730 J/g°C

Initial temperature of the sample = 88.6°C

Mass of the water = 300.0 grams

Initial temperature = 25.0°C

Specific heat capacity of water = 4.184 J/g°C

<u>Step 2:</u> Calculate final temperature

Qlost = -Qgained

Qquartz = - Qwater

Q =m*c*ΔT

Q = m(quartz)*c(quartz)*ΔT(quartz) = -m(water) * c(water) * ΔT(water)

⇒ mass of the quartz = 48.0 grams

⇒ c(quartz) = the specific heat capacity of quartz = 0.730 J/g°C

⇒ ΔT(quartz) = The change of temperature of the sample = T2 -88.6 °C

⇒ mass of water = 300.0 grams

⇒c(water) = the specific heat capacity of water = 4.184 J/g°C

⇒ ΔT= (water) = the change in temperature of water = T2 - 25.0°C

48.0 * 0.730 * (T2-88.6) -300.0 * 4.184 *(T2 - 25.0)

35.04(T2-88.6) = -1255.2 (T2-25)

35.04T2 -3104.544 = -1255.2T2 + 31380

1290.24T2 = 34484.544

T2 = 26.7 °C

The equilibrium temperature of the water is 26.7 °C

8 0
2 years ago
PLZZZZZZZZZZZZZZZ HELP IF RIGHT WILL GIVE BRAINLIEST
ioda

Answer:

I guess it all of these

as life cycle of an organism can be predicted and yeah it begins with birth hatching or germination for mammals, animals and plants respectively. then it's same for the organism of the same species .

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