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Grace [21]
2 years ago
6

Give the hybridization for the c in hcch. group of answer choices

Chemistry
1 answer:
Tamiku [17]2 years ago
5 0

The hybridization for C in acetylene, HCCH, or C₂H₂ is 'sp'.

Discussion:

There are three different forms of hybridization -

  1. sp- The first occurs when two carbon atoms are triple linked.
  2. sp₂- When two carbon atoms are double-bonded to one another, this is known as sp₂.
  3. sp₃- When a single bond joins two carbon atoms, this is known as sp₃.

In the case of acetylene(HCCH or C₂H₂):

  • The carbon atom requires additional electrons to establish four bonds with hydrogen and other carbon atoms in the synthesis of C₂H₂. One 2s₂ pair is consequently transferred to the vacant 2pz orbital. Each carbon has two sp hybrid orbitals after the 2s orbital in each atom combines with one of the 2p orbitals.
  • As a result of the atoms' symmetrical alignment in a single plane, C₂H₂ possesses a linear molecular structure. Due to their lower electronegative nature than Hydrogen atoms, all Carbon atoms are situated near the center of the Lewis structure of C₂H₂.

                                              H-C≡C-H

Therefore, it is concluded from the above discussion that the hybridization type of acetylene is 'sp'.

Learn more about hybridization here:

brainly.com/question/14140731

#SPJ4

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There you go! I really hope this helped, if there’s anything just let me know! ☻
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3 years ago
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Answer:

If the volume is doubled and the number of molecules is doubled, pressure is unchanged

Explanation:

Step 1: Data given

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Step 2:

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Initial pressure = n*R*T / V

Initial pressure = 2*R*T/2

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Final pressure = 4*RT / 4

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3 0
3 years ago
If a car travels 400m in 20 seconds, how fast is it going
prohojiy [21]

Answer:

Just apply the formula

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this is the way to do it

3 0
3 years ago
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The rate of effusion of an unknown gas was measured and found to be 11.9 mL/min. Under identical conditions, the rate of effusio
iren2701 [21]

Answer : The correct option is, (B) CO_2

Solution :

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or,

(\frac{R_1}{R_2})=\sqrt{\frac{M_2}{M_1}}       ..........(1)

where,

R_1 = rate of effusion of unknown gas = 11.9\text{ mL }min^{-1}

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Now put all the given values in the above formula 1, we get:

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Answer:

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