Question

You have separate solutions of hcl and h2so4 with the same concentrations in terms of molarity. you wish to neutralize a solution of naoh. which acid solution would require more volume (in ml) to neutralize the base?

Answer 1

HCl + NaOH = NaCl + H₂O

H₂SO₄ + 2NaOH = Na₂SO₄ + 2H₂O ⇒ 0.5H₂SO₄ + NaOH = 0.5Na₂SO₄ + H₂O

V(HCl)=2V(H₂SO₄)

The volume of the hydrochloric acid solution (HCl) is twice as large as the volume of the sulfuric acid solution (H₂SO₄).

Answer 2

Answer:

The sodium hydroxide under equal concentrations

Explanation:

Hello,

At first, lets consider the neutralization reactions for the involved acids with sodium hydroxide:

$NaOH+HCl-->NaCl+H_2O\\2NaOH+H_2SO_4-->Na_2SO_4+2H_2O$

As you can see the mole ration between hydrochloric acid and sodium hydroxide is 1 to 1, it means that for equal concentations, the volume of acid will equal the volume of base. However, for sulfuric acid we have a 2 to 1 ratio (2 moles of hydroxide per 1 mole of acid), it means that for equal concentrations, the half of sulfuric acid's volume will be required to neutralize the sodium hydroxide. In such a way, the hydrochloric acid's solution will require more volume to neutralize the sodium hydroxide under equal concentrations.

Best regards.