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1 year ago

Question 11

Physics

1 answer:

notka56 [123]1 year ago

3 0

The volume of the gas once it reaches the surface of water is 2 liters.

The volume of the air in balloon at depth of 100ft (30m) is 500ml.

The pressure at this point is 4 atm.

Assuming that the balloon have no compression by rubber of balloon the volume of air at the water surface is V.

The pressure at the surface of water is 1 atms.

As we know, from the ideal gas equation,

PV = nRT

Where,

P is the Pressure of gas,

V is the volume of the gas,

n is the number of moles,

R is the gas constant whose value is 0.082057 L atm mol-1 K-1,

T is the temperature.

Assuming that the temperature is constant,

We know,

PV = nRT

All quantities on the right side are constants,

So, we can write,

P₁V₁ = P₂V₂

Putting all the the values,

4(0.5) = 1V₂

V₂ = 2 Liters.

The volume of the air at the surface is 2 liters.

1 liter = 0.001 m

Hence,

2 liters = 0.002 m³

So the volume of air at the surface is 0.002m³.

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Superconducting cables conduct current with no resistance. Consequently, it is possible to pass huge currents through the cables

sergeinik [125]

Answer:

Explanation:

Force per unit length between two cables at distance d carrying current I₁ and I₂ can be given by the following expression .

F = 10⁻⁷ x 2I₁ I₂ / d

I₁ = I₂ = 15000 A

F = 10⁻⁷ x 2I₁ I₂ / d

= 10⁻⁷ x 2 x 15000² / 4.5 x 10⁻³ m

= 10000 N .

It will be repelling force ie they will repel each other because current is in opposite direction .

No , we should not be concerned about mechanical strength because force does not depend on it .

4 0

3 years ago

A pin-supported, vertically-oriented 1-m long thin rod is struck by a pellet at m down from the pin at the top. The mass of the

Natasha_Volkova [10]

Answer:

the angular velocity of the rod immediately after being struck by the pellet, provided that the pellet gets lodged in the rod is = 0.5036 k` rad/s

Explanation:

Using the conservation of momentum of approach.

From the question; the pellet is hitting at a distance of 0.4 m down from the point of rotation of the rod.

So, the angular momentum of the system just before the collision occurs with respect to the axis of the rotation is expressed by the formula:

$L_i ^ { ^ \to } = mp ( r_y } ^ { ^ \to } * v_{pi} ^ { ^ \to } )$ ----- equation (1)

The position vector can now be :

$x ^ { ^ \to }$ = $- 0.4 \ j \ m$

Also, given that :

$v_{p,i} ^ { ^ \to } = (280 \ i - 350 \ j) \ m/s$

Replacing the value into above equation (1); we have:

$L_i ^ { ^ \to } =0.012 ((- \ 0.4 \ j) *(280 \ i - 350 \ j ))$

$L_i ^ { ^ \to } =0.012 * 112 \ k$ (by using cross product )

$L_i ^ { ^ \to } = 1.344 k` \ \ kg m^2 s^{-1}$

However; the moment of inertia of the rod about the axis of rotation is :

$I_{rod} = \frac{1}{3}m_rl^2 \\ \\ I_{rod} = \frac{1}{3}*8*1^2 \\ \\ I_{rod} = \frac{8}{3} \ \ kg \ m^2$

Also, the moment of inertia of the pellet about the axis of rotation is:

$I_{pellet} = m_pr_y^2 \\ \\ I_{pellet} = 0.012 *0.4^2 \\ \\ I_{pellet} = 1.92*10^{-3} kg . m^2$

So, the moment of inertia of the rod +pellet system is:

$I = I_{rod}+I_{pellet}$

$I =( \frac{8}{3}+1.92 *10^{-3} )kg. m^2$

$I = 2.6686 \ kg. m^2$

The final angular momentum is :

$L_f ^ {^ \to} = I \omega { ^ {^ \to} } = 2.6686 \ \omega ^ {^ \to}$

The angular velocity of the rod $\omega$ is determined by equating the angular momentum just before the collision with the final angular momentum (i.e after the collision).

So;

$L_f ^ {^ \to} = L_i ^ { ^ \to}$

$2.6686 \omega ^ {^ \to} = 1.344 \ k ^ {^ \to}$

$\omega ^ {^ \to} = \frac{1.344 \ k`}{2.6686}$

= 0.5036 k` rad/s

Hence; the angular velocity of the rod immediately after being struck by the pellet, provided that the pellet gets lodged in the rod is = 0.5036 k` rad/s

7 0

4 years ago

an object is moving with a speed of 35 m/s and has a kinetic energy of 1500 J, what is the mass of the object?

Elena-2011 [213]

You'd use the equation kinetic energy=mass*0.5*speed^2
So you'd rearrange this to get mass =kinetic energy /0.5 *speed^2
Which is mass= 1500J/0.5*35^2
=2.44897959183673469........kg

5 0

3 years ago

A balloon is filled with a gas at 111 kPa when the temperature was 22*C. If the temperature

storchak [24]

119.7kPa

Explanation:

Given parameters:

Pressure of gas in balloon = 111kPa

Temperature of gas = 22°C

Final temperature = 45°C

Unknown:

Final pressure = ?

Solution:

Since the gases in the balloon have the same number of moles. We can apply a derivative of the combined gas law to solve this problem.

At constant volume the pressure of a given mass of gas varies directly with the absolute temperature.

$\frac{P1}{T1} = \frac{P2}{T2}$

P1 is the initial pressure

P2 is the final pressure

T1 is the initial temperature

T2 is the final temperature

convert from celcius to kelvin:

tK = 273 + tC

T1 = 273 + 22 = 295K

T2 = 273 + 45 = 318K

$\frac{111}{295} = \frac{P2}{318}$

P2 = 119.7kPa

learn more:

Ideal gas brainly.com/question/13064292

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3 0

3 years ago

Atoms of an element contain only one type of atom because they each contain the same number of

stich3 [128]

Answer:

I believe it is B

Explanation:

3 0

4 years ago