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tia_tia [17]
3 years ago
13

You might say that this experiment was an attempt to build a scale, and then calibrate it against a scale that we trust (the ele

ctronic scale). So as not to give away the answer to the preceding question, let's assume that we're talking about a different scale with the same design. Several trials are conducted, and the average and 95% confidence interval are calculated. The mass determined using this other balance scale does NOT agree with the mass measured on a digital scale. Is it possible that the balance scale and the electric scale are accurate, and the lack of agreement was just random?
Physics
2 answers:
hammer [34]3 years ago
8 0

Answer:

yes

Explanation:

Allushta [10]3 years ago
3 0

No.

Since repeated measurements are taken and the average and 95% confidence interval are calculated, the possibility of the lack of agreement being a random error has been minimized or even eliminated.

<h3>What is a random error?</h3>

Random error is defined as the deviation of the total error from its mean value due to chance.

Random errors can result from the instrument not being precise or from mistakes by the researcher.

Random errors can be minimized by taking multiple readings and averaging the results.

Since repeated measurements are taken and the average and 95% confidence interval are calculated, the possibility of the lack of agreement being a ransom error has been minimized.

Learn more about random errors at: brainly.com/question/22041172

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Firlakuza [10]
The zygomaticus muscle <span> pulls the corners of the mouth upward

Zygomaticus muscle is the muscle that is responsible in making us smile, The muscle started from the malar bone and stretched up to the corner part of our upper lip and will make reflective response that is sent by your brain.</span>
5 0
3 years ago
Help me <img src="https://tex.z-dn.net/?f=%5Chuge%5Cmathcal%5Cred%7B%7D" id="TexFormula1" title="\huge\mathcal\red{}" alt="\huge
elixir [45]

Answer:

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8 0
2 years ago
To what temperature must you raise a silver wire (c = 0.0038), originally at 20.0°C, to double its resistance, neglecting any ch
balu736 [363]

Answer:

T=283^{\circ}C

Explanation:

Given a material with temperature coefficient of resistance <em>c</em>, the equation that relates the resistance R_0 at temperature T_0 and the resistance R at temperature T is

\frac{R-R_0}{R_0}=c(T-T_0)

We want to double our resistance, so R=2R_0, thus having:

\frac{2R_0-R_0}{R_0}=\frac{R_0}{R_0}=1=c(T-T_0)

For this T must be:

1=cT-cT_0

T=\frac{1+cT_0}{c}

which for our values means (with T=20^{\circ}C=293^{\circ}K, remember to write temperature in S.I., and that for silver c=0.0038^{\circ}K^{-1}):

T=\frac{1+(0.0038^{\circ}K^{-1})(293^{\circ}K)}{(0.0038^{\circ}K^{-1})}=556^{\circ}K=283^{\circ}C

3 0
3 years ago
Please help!! For a science quiz
klio [65]

1.Velocity (v) is a vector quantity that measures displacement (or change in position, Δs) over the change in time (Δt), represented by the equation v = Δs/Δt. Speed (or rate, r) is a scalar quantity that measures the distance traveled (d) over the change in time (Δt), represented by the equation r = d/Δt.

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3 years ago
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zheka24 [161]

Answer:

The speed is 173 m/s.

Explanation:

Given that,

A = 47

B = 14

Length 1 urk = 58.0 m

An hour is divided into 125 time units named dorts.

3600 s = 125 dots

dorts = 28.8 s

Speed v= (25.0+A+B) urks/dort

We need to convert the speed into meters per second

Put the value of A and B into the speed

v=25.0+47+14

v =86\ urk s/dort

v=86\times\dfrac{58.0}{28.8}

v=173.19\ m/s

Hence, The speed is 173 m/s.

7 0
3 years ago
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