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alina1380 [7]
3 years ago
14

Which particle would have the slowest rate of deposition? A.round particle B.very large particle C.particle with sharp ends D.pa

rticle with a high density
Physics
2 answers:
Neko [114]3 years ago
8 0

Answer:

C.particle with sharp ends is the correct answer

Explanation:

particle with sharp ends would have the slowest rate of deposition.

The frictional force which is important that gives resistance to the movement will be higher for irregularly shaped particles and this is the reason sharp ends particles have the slowest rate of deposition.

Deposition happens when the particles settle down on a solid surface.

Density is directly proportional to deposition it means that the particles with high density settle faster and particle with sharp end has lower density so that the reason they have slowest deposition rate.

lisabon 2012 [21]3 years ago
3 0

The particle with sharp ends have the slowest rate of deposition  

Answer: Option C  

<u>Explanation:</u>

          As per aerosol physics, deposition is a process where aerosol particles accumulate or settle on solid surfaces. Thereby, it reduces the concentration of particles in the air. Deposition velocity (rate of deposition) defines from F = vc, where v is deposition rate, F denotes flux density and c refers concentration.  

          Deposition velocity is slowest for particles of intermediate-sized particles because the frictional force offers resistance to the flow. Density is directly proportional to the deposition rate so clearly shows that high-density particles settle faster. Due to friction, round and large-sized particles deposit faster than oval/flattened sediments.  

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3 years ago
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Two flat 4.0 cm × 4.0 cm electrodes carrying equal but opposite charges are spaced 2.0 mm apart with their midpoints opposite ea
serious [3.7K]

Answer:

1.77 x 10^-8 C

Explanation:

Let the surface charge density of each of the plate is σ.

A = 4 x 4 = 16 cm^2 = 16 x 10^-4 m^2

d = 2 mm

E = 2.5 x 10^6 N/C

ε0 = 8.85 × 10-12 C2/N ∙ m2

Electric filed between the plates (two oppositively charged)

E = σ / ε0

σ = ε0 x E

σ = 8.85 x 10^-12 x 2.5 x 10^6 = 22.125 x 10^-6 C/m^2

The surface charge density of each plate is ± σ / 2

So, the surface charge density on each = ± 22.125 x 10^-6 / 2

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Charge on each plate = Surface charge density on each plate x area of each plate

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7 0
3 years ago
Variables in physics often include a subscript. What are subscripts used for in physics?
Viefleur [7K]

Answer:

C.) To indicate different versions of the same variable.

Explanation:

Variables in physics often include a subscript. These subscripts are used for indicating different versions of the same variable in physics.

Basically, subscripts are used to represent the beginning (initial) and ending (final) position or point of a variable in physics.

For example, we would look at Gay Lussac' Law of gases.

Gay Lussac law states that when the volume of an ideal gas is kept constant, the pressure of the gas is directly proportional to the absolute temperature of the gas.

Mathematically, Gay Lussac's law is given by;

PT = K

\frac{P1}{T1} = \frac{P_{2}}{T_{2}}

Where;

T_{1} represents the initial temperature.

T_{2} represents the initial temperature.

P_{1} represents the initial pressure.

P_{2} represents the initial pressure.

Note: 1 and 2 are the subscript while T and P are the variables.

4 0
3 years ago
A bicycle traveled 150 meters west from point A to point B. Then It took the same route and came back to point A. It took a tota
Julli [10]

Answer:

Option D.  The average speed is 2.5 meters/second, and the average velocity is  0 meters/second.

Explanation:

we know that

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Remember that

1\ min=60\ sec

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substitute

s=\frac{300}{120}

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To find out the average velocity divide the displacement) by the time

The displacement is the distance from the start point to the end point regardless of the route

In this problem

The start point is A and the end point is A

so

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2 years ago
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katrin [286]

Answer:

Loudness of the second sound is more than the first one.

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As the loudness depends on the amplitude of the sound so the loudness of the second sound is more than the first sound.

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