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Alex
3 years ago
6

the crust is the thinnest layer on Earth, which allowed it to have a more constant theory of its composition. how do you think s

cientists have gathered all of the evidence on the crust?
Physics
1 answer:
OlgaM077 [116]3 years ago
3 0

Answer:

Explanation:

Geologists record the seismic waves and study how they travel through Earth. The speed of these seismic waves and the paths they take reveal how the planet is put together. Using data from seismic waves, geologists have learned that Earth's interior is made up of several layers.

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A flock of ducks is trying to migrate south for the winter, but they keep being blown off course by a wind blowing from the west
Minchanka [31]

The ducks' flight path as observed by someone standing on the ground is the sum of the wind velocity and the ducks' velocity relative to the wind:

ducks (relative to wind) + wind (relative to Earth) = ducks (relative to Earth)

or equivalently,

\vec v_{D/W}+\vec v_{W/E}=\vec v_{D/E}

(see the attached graphic)

We have

  • ducks (relative to wind) = 7.0 m/s in some direction <em>θ</em> relative to the positive horizontal direction, or

\vec v_{D/W}=\left(7.0\dfrac{\rm m}{\rm s}\right)(\cos\theta\,\vec\imath+\sin\theta\,\vec\jmath)

  • wind (relative to Earth) = 5.0 m/s due East, or

\vec v_{W/E}=\left(5.0\dfrac{\rm m}{\rm s}\right)(\cos0^\circ\,\vec\imath+\sin0^\circ\,\vec\jmath)

  • ducks (relative to earth) = some speed <em>v</em> due South, or

\vec v_{D/E}=v(\cos270^\circ\,\vec\imath+\sin270^\circ\,\vec\jmath)

Then by setting components equal, we have

\left(7.0\dfrac{\rm m}{\rm s}\right)\cos\theta+5.0\dfrac{\rm m}{\rm s}=0

\left(7.0\dfrac{\rm m}{\rm s}\right)\sin\theta=-v

We only care about the direction for this question, which we get from the first equation:

\left(7.0\dfrac{\rm m}{\rm s}\right)\cos\theta=-5.0\dfrac{\rm m}{\rm s}

\cos\theta=-\dfrac57

\theta=\cos^{-1}\left(-\dfrac57\right)\text{ OR }\theta=360^\circ-\cos^{-1}\left(-\dfrac57\right)

or approximately 136º or 224º.

Only one of these directions must be correct. Choosing between them is a matter of picking the one that satisfies <em>both</em> equations. We want

\left(7.0\dfrac{\rm m}{\rm s}\right)\sin\theta=-v

which means <em>θ</em> must be between 180º and 360º (since angles in this range have negative sine).

So the ducks must fly (relative to the air) in a direction 224º relative to the positive horizontal direction, or about 44º South of West.

8 0
3 years ago
What is defined as the isolation and reduction of variables in an experiment in order to understand the impact of a specific var
ehidna [41]

aisnhsjdjxbxbxhxbxjx

7 0
3 years ago
If a rock is thrown upward on the planet Mars with a velocity of 10 m/s, its height in meters t seconds later is given by y= 10t
spin [16.1K]

Answer:

a)

i) v = 4.42 m/s

ii) v = 5.36 m/s

iii) v = 6.1 m/s

iv) v = 6.26 m/s

v) v = 6.28 m/s

b) The instantaneous velocity at t = 1 is 6.28 m/s

Explanation:

a) The average velocity is the variation of the position over time. It is expressed as follows:

v = Δy/Δt

Where

v = average velocity

Δy = displacement = final position - initial position

Δt = variation of time = final time - initial time

i) Let´s find the position at both times and then apply the equation for the average velocity:

y(t) = 10 · t - 1.86 · t²

y(1 s) = 10 m/s · 1 s - 1.86 m/s² · (1 s)²

y = 8.14 m

y (2 s) = 10 m/s · 2 s - 1.86 m/s² · (2 s)²

y = 12.56 m

Then, the average velocity  will be:

v = final position - initial position / final time - initial time

v = 12.56 m - 8.14 m / 2 s - 1 s = 4.42 m/s

ii) We proceed in the same way as in i)

y(1.5 s) = 10 m/s · 1.5 s - 1.86 m/s² · (1.5 s)²

y = 10.82 m

v = 10.82 m - 8.14 m / 1.5 s - 1 s = 5.36 m/s

iii)

y(1.1 s) = 10 m/s · 1.1 s - 1.86 m/s² · (1.1 s)²

y = 8.75 m

v = 8.75 m - 8.14 m / 1.1 s - 1 s = 6.1 m/s

iv)

y(1.01 s) = 10 m/s · 1.01 s - 1.86 m/s² · (1.01 s)²

y = 8.20 m

v = 8.20 m - 8.14 m / 1.01 s - 1 s = 6 m/s ( 6.26 m/s without rounding the y-final value)

v)

y(1.001 s) = 10 m/s · 1.001 s - 1.86 m/s² · (1.001 s)²

y = 8.146

v = 8.146 m - 8.14 m  / 1.001 s - 1 s = 6 m/s  (6.28 m/s without rounding the value of y-final)

b) The instantaneous velocity is given by the derivative of the position function:

y = 10 · t - 1.86 · t²

dy/dt = 10 - 2 · 1.86 · t  = 10 - 3.72 · t

At t = 1

v = 10 m/s - 3.72 m/s² · 1 s = 6.28 m/s

4 0
3 years ago
calculate the magnitude of the electric field intensity in vacuum at a distance of 20 cm from a charge of 5 * 10 raise to power
forsale [732]

Answer:

1.1259*10^9 Newton per Columb

Explanation:

the magnitude of the electric field intensity can be calculated using the expresion below;

E=Kq/r^2

Where k= constant

q= electric charge

r=distance= 2cm= 20*10^-2m( we convert to m for unit consistency

:,K=59*10^9 Columb

If we substitute the value into above formula we have

E=(9*10^9)*(5*10^-3)/(20*10^-2)^2

=1.1259*10^9 Newton per Columb

Therefore,the magnitude of the electric field intensity in vacuum at a distance of 20 cm is 1.1259*10^9 Newton per Columb

3 0
3 years ago
(1 point) Find a linearly independent set of vectors that spans the same subspace of R3R3 as that spanned by the vectors ⎡⎣⎢3−1−
Natalka [10]

Answer:

Explanation:

A=\left[\begin{array}{ccc}3&-9&-3\\-1&2&0\\-2&3&-1\end{array}\right] \\\\R_2\rightarrow 3R_2+R_1,R_3\rightarrow 3R_3+2R_1\\\\=\left[\begin{array}{ccc}3&-9&-3\\0&-3&-3\\0&-9&-9\end{array}\right] \\\\R_3\rightarrow 3R_3-9R_2\\\\=\left[\begin{array}{ccc}3&-9&-3\\0&-3&-3\\0&0&0\end{array}\right]

This is the row echelon form of A. This means that only two of the vectors in our set are linearly independent. In other words, the first two vectors alone will span the same subspace of R^4 as all three vectors.

Therefore, the linearly independent spanning set for the subspace is

\left[\begin{array}{ccc}3\\-1\\-2\end{array}\right] \left[\begin{array}{ccc}-9\\2\\3\end{array}\right] \left[\begin{array}{ccc}3\\0\\-1\end{array}\right]

5 0
3 years ago
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