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3 years ago

9

We have a 10kg ball and a 15kg ball. We drop them from the top of the science building while objects are at rest and there is no

wind resistance. Which one hits the ground first?

1 answer:

Mashcka [7]3 years ago

3 0

They will hit the ground at the same time, as mass is negligible when calculating the acceleration of gravity when there is no air resistance

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A 0.600 m long pendulum is used to determine the acceleration due to gravity on a distant plane. If 20 oscillations are complete

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Answer:

7.50 m/s^2

Explanation:

The period of a pendulum is given by:

$T=2\pi \sqrt{\frac{L}{g}}$ (1)

where

L = 0.600 m is the length of the pendulum

g = ? is the acceleration due to gravity

In this problem, we can find the period T. In fact, the frequency is equal to the number of oscillations per second, so:

$f=\frac{N}{t}=\frac{20}{35.5 s}=0.563 Hz$

And the period is the reciprocal of the frequency:

$T=\frac{1}{f}=\frac{1}{0.563 Hz}=1.776 s$

And by using this into eq.(1), we can find the value of g:

$g=\frac{4 \pi^2 L}{T^2}=\frac{4 \pi^2 (0.600 m)}{(1.776 s)^2}=7.50 m/s^2$

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Answer:

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A beam of light has a wavelength of 650 nm in vacuum. (a) What is the speed of this light in a liquid whose index of refraction

Lady_Fox [76]

Answer:

The speed of this light and wavelength in a liquid are $2.04\times10^{8}\ m/s$ and 442 nm.

Explanation:

Given that,

Wavelength = 650 nm

Index refraction = 1.47

(a). We need to calculate the speed

Using formula of speed

$n = \dfrac{c}{v}$

Where, n = refraction index

c = speed of light in vacuum

v = speed of light in medium

Put the value into the formula

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$v=\dfrac{3\times10^{8}}{1.47}$

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Using formula of wavelength

$n=\dfrac{\lambda_{0}}{\lambda}$

$\lambda=\dfrac{\lambda_{0}}{n}$

Where, $\lambda_{0}$ = wavelength in vacuum

$\lambda$ = wavelength in medium

Put the value into the formula

$\lambda=\dfrac{650\times10^{-9}}{1.47}$

$\lambda=442\times10^{-9}\ m$

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Answer:

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<em>Taking the downward direction as positive</em>

<u>We are given:</u>

Initial velocity of the marble (u) = 0 m/s

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<u>Solving for the Final velocity:</u>

<u>Acceleration of the Marble:</u>

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<u>Final velocity:</u>

v = u + at [First equation of motion]

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