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Andreas93 [3]
1 year ago
13

I have to write chemical formula and the electron-dot for each of the product and also show electric charge if ions are formed

Chemistry
1 answer:
Ilya [14]1 year ago
8 0

bnswer

a. O +O / → O₂

b. K + Cl → KCl

c. C + O → CO

d. H + F → HF

e. I + I → I₂

f. S + O + O → SO₂

g. Na + Na + S → Na₂S

h. Li + Cl → LiCl

i. Ca + Br + Br → CaBr₂

j. N + N → N₂

A

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Which represents the balanced nuclear equation for the beta plus decay of C-11?
slavikrds [6]
Nuclear reaction: ¹¹C → ¹¹B + e⁺(positron) + ve(electron neutrino).<span><span><span><span>
</span></span></span></span>Beta decay is radioactive decay<span> in which a beta ray and a neutrino are emitted from an atomic nucleus.
There are two types of beta decay: beta minus and beta plus. In beta minus decay, neutron is converted to a proton and an electron and an electron antineutrino and in beta plus decay, a proton is converted to a neutron and positron and an electron neutrino, so mass number does not change.</span>
8 0
3 years ago
Read 2 more answers
Write and balance the half-reaction for the oxidation of white phosphorous P4 to the phosphate ion PO3^−4 in a basic solution.
aalyn [17]

Since the half-reaction is occurring in a basic solution, add 32OH− to each side of the equation to eliminate the H+ ions.

P₄ +16H₂O + 32OH⁻ ⟶ 4PO₃⁻⁴ + 32H⁺ +32OH⁻

Final reaction :

P₄ + 32OH⁻ ⟶ 4PO₃⁻⁴ + 16H₂O + 20e⁻

A half reaction is either the oxidation or reduction reaction component of a redox reaction. A half reaction is obtained by considering the change in oxidation states of individual substances involved in the redox reaction.

The concept of half-reactions is used to describe what occurs in an electrochemical cell, such as a Galvanic cell battery. Half-reactions can be written to describe both the metal undergoing oxidation (known as the anode) and the metal undergoing reduction (known as the cathode).

Half-reactions are often used as a method of balancing redox reactions. For oxidation-reduction reactions in acidic conditions, after balancing the atoms and oxidation numbers, one will need to add H+ ions to balance the hydrogen ions in the half reaction.

For oxidation-reduction reactions in basic conditions, after balancing the atoms and oxidation numbers, first treat it as an acidic solution and then add OH- ions to balance the H+ ions in the half reactions (which would give H2O).

Learn more about Half reactions here : brainly.com/question/2491738

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3 0
2 years ago
In fossil comparisons, it helps to know about similar:
omeli [17]

Answer:

Fossils tell us when organisms lived, as well as provide evidence for the Fossils are the preserved remains or traces of animals, plants, and other organisms from the past. Fossils, by comparing the anatomies of both modern and extinct species, allows scientists to study the skin, hair, and organs of ancient creatures.

Explanation:

6 0
2 years ago
Which of the following features is common to both acids and bases? A. ability to burn skin B. similar taste C. pH measurements g
Lynna [10]
<h3>Answer:</h3>

            Correct Option-A (Ability to burn skin)

<h3>Explanation:</h3>

                    When skin tissues are exposed to Acids or Bases a chemical burn occurs as both of these substances are corrosive in nature. These burns occur without providing any heat, results from a very fast reaction, are extremely painful and causes damage to structures present under skin.

                    Option-B is incorrect because Acids taste sour, while, Bases taste bitter.

                    Option-C is incorrect because pH of Acids is less than 7 while, pH of Bases is greater than 7.

3 0
3 years ago
Read 2 more answers
What mass of sodium hydroxide is needed to neutralise 24.5kg of sulfuric acid <br> H2SO4 + N2 = 2NH3
sveticcg [70]

Answer:

23.92 g

Explanation:

Molar mass of H2SO4 = (2×1)+32+(16×4)= 2+32+48= 82g/mol

H2SO4 + 2NaOH ---> Na2SO4 + 2H2O

I mole of H2SO4 = 2 moles of NaOH

24.5/82 = 24.5/82 × 2

= 0.598 moles of NaOH will neutralize

Mass= mole× molar mass

Molar mass of NaOH= 23+16+1 = 40g/mol

Mass= 0.598 × 40 = 23.92g of NaOH

7 0
3 years ago
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