Answer: I believe it is A.
Explanation:
Answer:
A. mass X to moles X to moles Y to liters Y
Explanation:
Remember: moles are the great converter. They're basically just a made-up concept meant to facilitate conversions!
Starting with mass X, you must then convert to moles X.
Once you have moles X, convert moles Y. Think of a chemical equation: the mole ratios are the coefficients!
Once you have moles Y, all you have to do is convert to liters Y. You can do this with the molarity equation M = mol/L, or if it's a gas at STP you know the conversion!
-130KJ is the standard heat of formation of CuO.
Explanation:
The standard heat of formation or enthalpy change can be calculated by using the formula:
standard heat of formation of reaction = standard enthalpy of formation of product - sum of enthalpy of product formation
Data given:
Cu2O(s) ---> CuO(s) + Cu(s) ∆H° = 11.3 kJ
2 Cu2O(s) + O2(g) ---> 4 CuO(s) ∆H° = -287.9 kJ
CuO + Cu ⇒ Cu2O (-11.3 KJ) ( Formation of Cu2O)
When 1 mole Cu20 undergoes combustion 1/2 moles of oxygen is consumed.
Cu20 + 1/2 02 ⇒ 2CuO (I/2 of 238.7 KJ) or 119.35 KJ
So standard heat of formation of formation of Cu0 as:
Cu + 1/2 02 ⇒ CuO
putting the values in the equation
ΔHf = ΔH1 + ΔH2 (ΔH1 + ΔH2 enthalapy of reactants)
heat of formation = -11.3 + (-119.35)
= - 130.65kJ
-130.65 KJ is the heat of formation of CuO in the given reaction.
Avegadro's number = 6.02 x10^23 atoms
so
3.5g x 1mol/63.55g Cu x 6.02 x 10^23/ 1mol=3.32 x 10^22 atoms
<u>Answer:</u>
For 2: The correct answer is grams of solute per 100 grams of solvent.
For 3: The correct answer is supersaturated.
For 4: the correct answer is the solubility decreases.
<u>Explanation:</u>
Solubility is defined as the property which refers to the ability of the solute that can be dissolved in a solvent. It is defined as the number of grams of solute per 100 grams of solvent.
Unsaturated solution is defined as the solution in which amount of solute that is dissolved in the solvent is less.
Saturated solution is defined as the solution in which no more solute can be dissolved in the given amount of solvent.
Emulsion is defined as the dispersion of one liquid in another liquid in which it is not soluble.
Supersaturated solution is defined as the solution in which solvent contains more amount of solute than the required amount. These solutions help in the process of crystallization.
When a crystal is added to a <u>supersaturated solution</u>, more and more particles come out of the solution and this process is known as crystallization.
According to the Henry's Law
The solubility of the gas in a liquid is directly proportional to the partial pressure of the gas.
![\text{Solubility of a gas in a liquid}\propto \text{Partial pressure of the gas}](https://tex.z-dn.net/?f=%5Ctext%7BSolubility%20of%20a%20gas%20in%20a%20liquid%7D%5Cpropto%20%5Ctext%7BPartial%20pressure%20of%20the%20gas%7D)
With increase in the partial pressure, the solubility of the gas in liquid also increases and vice-versa.
Hence, the correct answer is the solubility decreases.