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Crank
3 years ago
11

Identify the item that does not have kinetic energy.

Chemistry
1 answer:
d1i1m1o1n [39]3 years ago
4 0

Answer:

D

Explanation:

there is no other answer choice that does not move. This is a fool-proof question because all the other answer choices contain movement except the butterfly resting

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If 5.0 moles of C3H8 react, how many molecules of water are formed?
Lady_Fox [76]
 <span>Propane is C3H8 

The balanced equation is: 
C3H8 + 5 O2 --> 3 CO2 + 4 H2O 
From the balanced equation you can see that for each mole of C3H8 you obtain 4 moles of H2O. 

moles H2O = 5.0 moles C3H8(4 moles H2O/1 mole C3H8) = 20 moles H2O formed 

Use Avogadro's number to find the number of molecules. 
molecules H2O = 20 moles H2O(6.02 x 10^23 molecules/1 mole) = 1.20 x 10^25 H2O molecules</span><span>
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4 0
3 years ago
Which of the following best defines the term oxidation state?
eimsori [14]
C seems to be the best answer

4 0
3 years ago
Idk what is asking ?
castortr0y [4]
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4 0
3 years ago
Find the enthalpy of neutralization of HCl and NaOH. 87 cm3 of 1.6 mol dm-3 hydrochloric acid was neutralized by 87 cm3 of 1.6 m
olga nikolaevna [1]

Explanation:

The reaction equation for the given reaction will be as follows.

               HCl + NaOH \rightarrow NaCl + H_{2}O

Each mole of both HCl and NaOH gives one mole of water.

Also, it is given that 1 liter of NaOH and HCl solution contains 1.6 mol dm^{-3} of NaOH (HCl).

It is known that 1 cm^{3} = 0.001 liter. So, 87 cm^{3} = 0.087 liter.

Hence, number of moles of water obtained from the given reaction are as follows.

                  0.087 liter × 1.6 mol = 0.1392 moles

            No. of moles = \frac{mass}{molar mass of water}

                0.1392 moles = \frac{mass}{18 g/mol}

                       mass = 2.5056 g

Now, volume of water present before the reaction is 2 \times 0.087 liter = 0.174 liter or 0.174 Kg (as density is 1 Kg/cm^{3}) or 174 g (as 1 kg = 1000 g).

Therefore, total weight of water present = 2.5056 g + 174 g = 176.5056 g

Formula to calculate enthalpy of neutralization is as follows.

                Enthalpy of neutralization = mS \Delta T

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where,            m = mass

                       S = specific heat capacity

                   \Delta T = change in temperature

Putting the given values in the formula as follows.

       Enthalpy of neutralization = mS \Delta T

                     = 176.5056 g \times 4.18 J/K g \times (317.4 K - 298 K)              

                                                           = 14333.73 J

   or,                                                    = 14.33 kJ

Thus, we can conclude that the enthalpy of neutralization of given reaction is 14.33 kJ.

5 0
4 years ago
What does Bromine-80 decays by beta decay to?
nlexa [21]

Answer:

beta to Kr-80 or Se-80

Explanation:

sorry if wrong

7 0
3 years ago
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