Answer:
D. the quantity of heat that is required to raise 1 g of the sample by 1*C (kelvin) at a constant pressure.
Answer:
Root system will become larger or extend farther
Explanation:
If nutrient in soil decrease, the plant's roots system will likely become larger and extend out deeper and farther to get all the nutrients it possibly can
Exit here is the answer or this question
Answer:
The correct option is B
Explanation:
The reaction is given as

The equilibrium constant for this reaction is mathematically represented as
![K_c = \frac{[concentration \ of \ product ]}{concentration \ of \ reactant } = \frac{[fructose \ 6 -phosphate]}{[Glucose \ 6 - phosphate]}](https://tex.z-dn.net/?f=K_c%20%3D%20%5Cfrac%7B%5Bconcentration%20%5C%20of%20%20%5C%20product%20%5D%7D%7Bconcentration%20%5C%20of%20%20%5C%20reactant%20%7D%20%3D%20%5Cfrac%7B%5Bfructose%20%5C%206%20-phosphate%5D%7D%7B%5BGlucose%20%5C%206%20-%20phosphate%5D%7D)
From the question we are told that
[Glucose 6-phosphate] = 2 × [fructose 6-phosphate]
So
![K_c = \frac{[fructose \ 6 -phosphate]}{[2 (fructose \ 6 -phosphate)]} = 0.5](https://tex.z-dn.net/?f=K_c%20%20%3D%20%5Cfrac%7B%5Bfructose%20%5C%206%20-phosphate%5D%7D%7B%5B2%20%28fructose%20%5C%206%20-phosphate%29%5D%7D%20%3D%200.5)
Generally change in free energy
is mathematically represented as

Given that T = 298 K
R = 8.315 J/mol·K



Answer:
87.3
Explanation:
To calculate the relative atomic mass
((84.9*15)+(86.9*12.9)+(87.9*72.1))/15+12.9+72.1
(1273.5 + 1121.01 + 6337.59) / 100
8732.1/100
87.321 = 87.3