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katen-ka-za [31]
3 years ago
5

Consider the five balanced chemical reactions listed below, all using O2 as a reactant. Normally, O2 is an excess reagent for re

actions because there is a large amount of it available in the air. For this question, suppose that you have5.73 moles of O2 and1.70 moles of any of the other reactants in every equation. Select those equations below in which O2 would be the limiting reactant.
A.C6H12O6(s) + 6 O2(g) → 6 CO2(g) + 6 H2O(g)B.C3H8(g) + 5 O2(g) → 3 CO2(g) + 4 H2O(g)C.H2S(g) + 2 O2(g) → SO3(g) + H2O(g)D.4 NH3(g) + 5 O2(g) → 4 NO(g) + 6 H2O(g)E.None because in all the reactions O2 is in excess
Chemistry
1 answer:
ad-work [718]3 years ago
7 0

Answer: option E. None because in all the reactions O2 is in excess

Explanation:

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When a mixture of glucose 6-phosphate and fructose 6-phosphate is incubated with the enzyme phosphohexose isomerase, the final m
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The correct option is B

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             Glucose\ 6-phosphate ---->fractose \ 6-phosphate

The equilibrium constant for this reaction is mathematically represented as

               K_c = \frac{[concentration \ of  \ product ]}{concentration \ of  \ reactant } = \frac{[fructose \ 6 -phosphate]}{[Glucose \ 6 - phosphate]}

From the question we are told that

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what is the relative atomic mass of a hypothetical element that consists of the following isotopes in the indicated natural abun
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6 0
3 years ago
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