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katen-ka-za [31]
3 years ago
5

Consider the five balanced chemical reactions listed below, all using O2 as a reactant. Normally, O2 is an excess reagent for re

actions because there is a large amount of it available in the air. For this question, suppose that you have5.73 moles of O2 and1.70 moles of any of the other reactants in every equation. Select those equations below in which O2 would be the limiting reactant.
A.C6H12O6(s) + 6 O2(g) → 6 CO2(g) + 6 H2O(g)B.C3H8(g) + 5 O2(g) → 3 CO2(g) + 4 H2O(g)C.H2S(g) + 2 O2(g) → SO3(g) + H2O(g)D.4 NH3(g) + 5 O2(g) → 4 NO(g) + 6 H2O(g)E.None because in all the reactions O2 is in excess
Chemistry
1 answer:
ad-work [718]3 years ago
7 0

Answer: option E. None because in all the reactions O2 is in excess

Explanation:

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Calculate the wavelength of an electron (m = 9.11 x 10-28 g) moving at 3.66 x 100 m/s. A) 1.81 x 10-10 m B) 2.76 x 10-9 m C) 5.0
inna [77]

Answer:

option e = 1.99 × 10⁻⁶ m

Explanation:

Given data:

Mass of electron = 9.11 × 10⁻²⁸ g   or 9.11 × 10⁻³¹ Kg

Velocity = 3.66 × 100 m/s

Wavelength = ?

Solution:

Formula:

λ  = h / m. v

λ  = wavelength

h = planck's constant

m = mass

v = velocity

Now we will put the values in equation

λ  = h / m. v

λ  =  6.63 × 10⁻³⁴ Kg. m²/s  / 3.66 × 100 m/s . 9.11 × 10⁻³¹ Kg

λ  =  6.63 × 10⁻³⁴ Kg. m²/s / 3334.26  × 10⁻³¹ Kg .m/s

λ  = 1.99 × 10⁻⁶ m

7 0
3 years ago
Read 2 more answers
in a titration a 25.0 ml of 0.500 m khp is titrated to the equivalence point NaOH. The final solution volume is 35.5 mL. what is
borishaifa [10]
M2= 0.35M

Formula: M1 • V1 = M2 • V2

1) 25.0mL • .500M = 35.5mL • (x)

2) 12.5 = 35.5 • (x)

3) 12.5/35.5 = x

4) 0.35211 = x = M2

Hope this helps!
5 0
3 years ago
Non-conjugated β, γ-unsaturated ketones, such as 3-cyclohexenone, as in base-catalyzed equilibrium with their α,β-unsaturated is
uranmaximum [27]

Answer:

See the attached file for the structure.

Explanation:

Find attached for the explanation

7 0
4 years ago
There are ________ σ bonds and ________ π bonds in h3c-ch2-ch=ch-ch2-c≡ch.
FrozenT [24]
The number of sigma and pi bonds are,

          Sigma Bonds  =  16

          Pi Bonds         =   3

Explanation:
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Below all black bonds are sigma bonds, while in alkene there is one pi bond and in alkyne there are two pi bonds.

6 0
3 years ago
What type of energy source does electrolysis use?
BabaBlast [244]

Answer:

Explanation: Electrolysis uses DC electricity as a energy source.

4 0
4 years ago
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