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scZoUnD [109]
3 years ago
10

If the mass of a material is 76 grams and the volume of the material is 16 cm3, what would the density of the material be? g/cm3

Chemistry
1 answer:
mafiozo [28]3 years ago
6 0
4.8 g/cm3 with sig figs since it's mass/volume you divide 76 grams by 16 cm3
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What is the mass in grams of 9.76 x 10 12 atoms of naturally occurring sodium?
Fiesta28 [93]
The number of moles in a substance indicates the amount of the substance that contains the same number of particles as 12 g of the Carbon-12 isotope [or equivalent to 6.02 × 10²³] (which is used as a standard in the world of moles).

Now,

          if     6.02 × 10²³ atoms are found in 1 mole ofsodium
   then let  9.76 × 10¹² atoms are found in     x

⇒     x  =    (9.76 × 10¹² )  ÷  (6.02 × 10²³)

            =  1.619 × 10⁻¹¹ mol


Now, mass = moles × molar mass

∴ mass of Na = 1.619 × 10⁻¹¹ mol ×  23 g/mol
                      = 3.72 × 10⁻¹⁰ g


4 0
3 years ago
A balloon is filled with 0.75 L of Helium gas at 35 °C. If the temperature is increased to 113 °C, what thewill new volume be?
faust18 [17]

Answer: 0.9398 Liters

Explanation:

Charles' Law

V1/ T1 = V2/T2

0.75/35 = ?/113

0.75/35 = 0.9398/113

4 0
3 years ago
The diagram below shows part of the rock cycle. (6 points)
Anna35 [415]

Answer:

Igneous Rock

Explanation:

Assuming this is a cycle, the volcanic eruption would lead back to rock B; rocks formed by volcanic eruptions are considered Igneous.

4 0
3 years ago
Part III.The two reactions involved in quantitatively determining the amount of iodate in solution are: IO3-(aq) 5 I-(aq) 6 H (a
slega [8]

Answer:

\large \boxed{\math{\dfrac{\text{6 mol thiosulfate}}{\text{1 mol iodate}}}}

Explanation:

The I₂ is the common substance in the two equations.

(1) IO₃⁻ + 5I⁻ + 6H⁺ ⟶ 3I₂ + 3H₂O

{2) I₂ + 2S₂O₃²⁻ ⟶ 2I⁻ + S₄O₆²⁻

From Equation (1), the molar ratio of iodate to iodine is

\dfrac{\text{I}_{2}}{\text{IO}_{3}^{-}} = \dfrac{3}{1}

From Equation (2), the molar ratio of iodine to thiosulfate is

\dfrac{\text{S$_{2}$O}_{3}^{2-}}{\text{I}_{2}} = \dfrac{2}{1}

Combining the two ratios, we get

\text{Stoichiometric factor} = \dfrac{\text{S$_{2}$O}_{3}^{2-}}{\text{IO}_{3}^{-}} = \dfrac{\text{S$_{2}$O}_{3}^{2-}}{\text{I}_{2}} \times \dfrac{\text{I}_{2}}{\text{IO}_{3}^{-}} = \dfrac{2}{1} \times \dfrac{3}{1} = \mathbf{\dfrac{6}{1}}\\\\\text{The stoichiometric factor is $\large \boxed{\mathbf{\dfrac{\text{6 mol thiosulfate}}{\text{1 mol iodate}}}}$}

7 0
3 years ago
A compound is broken down by chemical means during
alexandr1967 [171]

Answer : Option 3) Electrolysis.


Explanation : In the process of electrolysis, decomposition of the chemical is done by passing the electric current from the liquid or the solution containing ions in it. This is the process where compound is broken into ions namely, cations and anions.


Rest all options does not involves chemical decomposition of the compound.


Chromatography is a technique where rates of solute and solvent are compared in a medium where the solute components move at different rates and the separation is obtained.


Distillation simply purifies the liquid or solution by heating or cooling process.


Filtration just involves removal of impurities by using a more porous material device to get purified compound.

6 0
3 years ago
Read 2 more answers
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