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scZoUnD [109]
3 years ago
10

If the mass of a material is 76 grams and the volume of the material is 16 cm3, what would the density of the material be? g/cm3

Chemistry
1 answer:
mafiozo [28]3 years ago
6 0
4.8 g/cm3 with sig figs since it's mass/volume you divide 76 grams by 16 cm3
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g A closed-end manometer was attached to a vessel containing argon. The difference in the mercury levels in the two arms of the
ElenaW [278]

Answer:

Answer: 882mmHg

Explanation:

In a closed-end manometer, the gas added is under a pressure that is measured against atmospheric pressure. The difference in pressure between both gases is equal to the difference in mercury levels. Thus, the pressure of the argon can be:

783 mmHg - 96.0mmHg = 687mmHg

783 mmHg - 96.0mmHg = 879mmHg

Based on the options, the possible answer (The nearest to the second value) is:

<h3>Answer: 882mmHg</h3>

7 0
3 years ago
Which one of the following reactions is NOT balanced?
Korolek [52]

Answer:

co+ o2+ 2co2 is not balanced reaction

6 0
3 years ago
Atoms can gain, lose, or share
Oksi-84 [34.3K]

Answer:

Atoms can gain, lose, or share electrons during a chemical change. Chemical changes do not affect the nucleus of an atom. For this reason, an atom has the ability to retain its properties or identity even if the number of electrons is different. Therefore, the atom's identity won't change.

Explanation:

6 0
3 years ago
What fraction of a Sr-90 sample remains unchanged after 87.3 years
jolli1 [7]
The answer is 1/8.

Half-life is the time required for the amount of a sample to half its value.
To calculate this, we will use the following formulas:
1. (1/2)^{n} = x,
where:
<span>n - a number of half-lives
</span>x - a remained fraction of a sample

2. t_{1/2} = \frac{t}{n}
where:
<span>t_{1/2} - half-life
</span>t - <span>total time elapsed
</span><span>n - a number of half-lives
</span>
The half-life of Sr-90 is 28.8 years.
So, we know:
t = 87.3 years
<span>t_{1/2} = 28.8 years

We need:
n = ?
x = ?
</span>
We could first use the second equation, to calculate n:
<span>If:
t_{1/2} = \frac{t}{n},
</span>Then: 
n = \frac{t}{ t_{1/2} }
⇒ n = \frac{87.3 years}{28.8 years}
⇒ n=3.03
<span>⇒ n ≈ 3
</span>
Now we can use the first equation to calculate the remained amount of the sample.
<span>(1/2)^{n} = x
</span>⇒ x=(1/2)^3
⇒x= \frac{1}{8}<span>
</span>
8 0
4 years ago
sarah measures out 151 grams of SO2. how many moles is this? Express your answer to three significant figures. ​
svp [43]

150 g SO₂ = 2.36 mol SO₂


M_r = 32.06 + 2×16.00 = 32.07 + 32.00 = 64.06


Moles of SO₂ = 151 g SO₂ × [1 mol SO₂/64.06 g SO₂] = 2.36 mol SO₂



4 0
3 years ago
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