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Alex Ar [27]
2 years ago
13

Two students, Jenny and Cho, are investigating motion.

Physics
1 answer:
IgorLugansk [536]2 years ago
8 0

Answer:

1: a measuring instruments the students should use for time is a stopwatch

2: a measuring instruments the students should use for distance is a measuring tape

Explanation:

pls mark brainliest

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What portion of the electromagnetic spectrum is most absorbed by the chlorophyll pigments in the thylakoid membranes?
nadya68 [22]

Answer: The visible part of the electromagnetic spectrum, <u>specifically blue and red wavelength</u>

Explanation:

Let's begin by explaining that pigments generally absorb more light than they reflect (they absorb certain wavelengths and reflect others). Therefore, the color that a given object seems to have depends on which parts of the visible electromagnetic spectrum are reflected and which parts are absorbed.

In this sense, in the thylakoid membranes there are two types of <u>chlorophyll pigments</u>:

-clorophyll b that absorbs the blue light of the electromagnetic spectrum

-clorophyll a that bsorbs the red light of the electromagnetic spectrum

That is why we generally see plants in green color and not in other colors.

4 0
3 years ago
Please help<br>Will give the brainliest!​
Ronch [10]

Answer:

both answer is option C

Explanation:

tag me brainliest

7 0
3 years ago
The maximum current output of a 60 ω circuit is 11 A. What is the root mean square voltage of the circuit?
goldenfox [79]

Answer:

660V

Explanation:

V=IR

V=?, I=11A,R=60w

V=60 ×11

=660V

8 0
3 years ago
What do you observe as you immerse the empty jug in a bucket which contains water? Explain why you observe this phenomenon. ​
liraira [26]

Answer:

The jug drowns because the density of the jug is more than that of the density of water.

7 0
3 years ago
Read 2 more answers
Find the wavelength of the balmer series spectral line corresponding to n = 15.
Anna71 [15]

Answer:

371.2 mm

Explanation:

The Balmer series of spectral lines is obtained from the formula

1/λ = R(1/2² -1/n²) where λ = wavelength, R = Rydberg's constant = 1.097 × 10⁷ m⁻¹

when n = 15

1/λ = 1.097 × 10⁷ m⁻¹(1/2² -1/15²)

    = 1.097 × 10⁷ m⁻¹(1/4 -1/225)

    = 1.097 × 10⁷ m⁻¹(0.25 - 0.0044)

    = 1.097 × 10⁷ m⁻¹ 0.245556

    = 2.693 10⁶ m⁻¹

So,

λ  = 1/2.693 10⁶ m⁻¹

    = 0.3712 10⁻⁶ m

    = 371.2 mm

7 0
3 years ago
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