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2 years ago

Which is correct gelp

Mathematics

1 answer:

myrzilka [38]2 years ago

8 0

Answer:

Step-by-step explanation:

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Mateo is constructing an equilateral triangle inscribed in a circle with center P. He draws the diameter of the circle through c

GenaCL600 [577]

Reading the question carefully, "He draws the diameter of the circle through center P using a straight edge. Next he opens his compass to a width equivalent to the radius of the circle." - that implies that Mateo is still in the process of drawing the circle by which the equilateral is inscribed to.

The next steps should be:
*He should draw the upper and lower arcs using the compass opened to a width equivalent to the radius of the sircle.
*Make a vertical diameter using centroid P as basis.
*Draw two right triangles facing the opposite directions using the top most point by which the vertical diameter of the circle touches the top most circumference of the circle.

Doing these steps, Mateo will be able to draw an equilateral triangle inscribed in a circle.

7 0

3 years ago

ASAP!! I need help. -w-Which answer choice shows 5 +0.9 + 0.06 written in standard form?

miss Akunina [59]

The answer is c . 5.96

7 0

3 years ago

Read 2 more answers

What two fractions make 1/3

Anna11 [10]

1/6 and 1/6 equals 1/3

8 0

3 years ago

A. > B. < C. = D. none of the above

earnstyle [38]

Answer:

$3.14 \times 10 ^{3} < 2.6 \times 10^{3}$

Step-by-step explanation:

$3.14 \times 10 ^{3}$

$3140$

$2.6 \times 10 ^{4}$

$26000$

7 0

2 years ago

Find the derivative of

kirill [66]

Answer:

$\displaystyle y'(1, \frac{3}{2}) = -3$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Coordinates (x, y)
Functions
Function Notation
Terms/Coefficients
Exponential Rule [Rewrite]: $\displaystyle b^{-m} = \frac{1}{b^m}$

Calculus

Derivatives

Derivative Notation

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Step-by-step explanation:

Step 1: Define

$\displaystyle y = \frac{3}{2x^2}$

$\displaystyle \text{Point} \ (1, \frac{3}{2})$

Step 2: Differentiate

[Function] Rewrite [Exponential Rule - Rewrite]: $\displaystyle y = \frac{3}{2}x^{-2}$
Basic Power Rule: $\displaystyle y' = -2 \cdot \frac{3}{2}x^{-2 - 1}$
Simplify: $\displaystyle y' = -3x^{-3}$
Rewrite [Exponential Rule - Rewrite]: $\displaystyle y' = \frac{-3}{x^3}$

Step 3: Solve

Substitute in coordinate [Derivative]: $\displaystyle y'(1, \frac{3}{2}) = \frac{-3}{1^3}$
Evaluate exponents: $\displaystyle y'(1, \frac{3}{2}) = \frac{-3}{1}$
Divide: $\displaystyle y'(1, \frac{3}{2}) = -3$

Topic: AP Calculus AB/BC (Calculus I/II)

Unit: Derivatives

Book: College Calculus 10e

6 0

2 years ago