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tino4ka555 [31]
1 year ago
14

Solve.

Mathematics
1 answer:
ArbitrLikvidat [17]1 year ago
3 0

The solution for the system equations is (2 , 0 , -2).

<h3>System of Equations</h3>

A system of equations is the given term math for two or more equations with the same variables. The solution of these equations represents the point of the intersection.

You can solve a system of equations by the adding or substitution methods. In the addition method, you eliminate a variable, on the other hand, in the substitution method you replace a variable for the other. To solve this question, you will apply the addition method.

The question gives three equations:

(1) 4x−2y+z=6

(2) −2x+y=−4

(3) 3y−2z=4

You should isolate the variable x in equation (2), then you will have

x=-\frac{-4-y}{2}. After that, you should use this variable in equation (1), see below

Equation 1 (4x−2y+z=6)

4(-\frac{-4-y}{2})-2y+z=6\\ \\ 8+2y-2y+z=6\\ \\ 8+z=6\\ \\ z=6-8\\ \\ z=-2

If z=-2, from equation (3), you find y, see below.

3y-2z=4

3y-2*(-2)=4

3y+4=4

3y=4-4

3y=0

y=0

If y=0, from equation (2), you find x, see below.

−2x+y=−4

-2x+0=-4

-2x=-4

x=2

Read more about solving systems equations here:

brainly.com/question/12691830

#SPJ1

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Is the following situation proportional? Justify your answer. At an arcade, Aisha pays $2 for each game she plays.
Over [174]

Yes, the situation as described is proportional.

Discussion:

According to the question:

  • We are required to determine if the situation described in the question is proportional.

Since, Aisha pays $2 for each game she plays at the arcade.

In essence, the total amount of money paid by Aisha will depend on the number of games she plays. On this note, the situation is proportional.

Read more on proportional:

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2 years ago
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3 years ago
Fill in the missing term in the equation
Y_Kistochka [10]

Answer:

<u>x</u>

Step-by-step explanation:

Let's simplify the LHS so it can be equated to the RHS.

\frac{x}{x^{2} -4x+4} - \frac{x}{x^{2} -3x+2}

\frac{x}{(x-2)^{2} } - \frac{x}{(x-1)(x-2)}

\frac{x(x-1)-x(x-2)}{(x-2)^{2}(x-1)}

\frac{x^{2} -x-x^{2}+2x }{(x-2)^{2}(x-1)}

\frac{x}{(x-2)^{2}(x-1)}

Hence, the missing term in the numerator of the answer is <u>x</u>

6 0
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Please help me with the question
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Answer: 70

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