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3 years ago

Which feature forms as a result of conduction between magma and water?

Chemistry

2 answers:

77julia77 [94]3 years ago

5 0

A hot spring is formed as a result of conduction between magma and water.

aleksley [76]3 years ago

5 0

Answer:

Explanation:

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stoichometry in chemistry!! please someone help i'm begging you, if i fail this then i fail chemistry

Anna71 [15]

Answer:

You can find in the given attachemnet

4 0

2 years ago

What is the volume of 13.21 g of ethane gas (C2H6) at STP?

yuradex [85]

The volume at STP : 9.856 L

<h3>Further explanation</h3>

Given

Mass of ethane : 13.21 g

Required

The volume at STP

Solution

Conditions at T 0 ° C and P 1 atm are stated by STP (Standard Temperature and Pressure). At STP, Vm is 22.4 liters / mol.

mol ethane(C2H6) :

= mass : molar mass

= 13.21 g : 30 g/mol

= 0.44

Volume at STP :

= 0.44 x 22.4 L

= 9.856 L

6 0

3 years ago

Describe all the relationships between pressure, volume, and temperature

hammer [34]

The pressure of a given amount of gas is directly proportional to its absolute temperature, provided that the volume does not change (Amontons's law).

 The volume of a given amount of gas is inversely proportional to its pressure when temperature is held constant (Boyle's law).

3 0

3 years ago

Read 2 more answers

What is the energy released in this β − β − nuclear reaction 40 19 K → 40 20 C a + 0 − 1 e 19 40 K → 20 40 C a + − 1 0 e ? (The

Effectus [21]

Answer: The energy released in the given nuclear reaction is 1.3106 MeV.

Explanation:

For the given nuclear reaction:

$_{19}^{40}\textrm{K}\rightarrow _{20}^{40}\textrm{Ca}+_{-1}^{0}\textrm{e}$

We are given:

Mass of $_{19}^{40}\textrm{K}$ = 39.963998 u

Mass of $_{20}^{40}\textrm{Ca}$ = 39.962591 u

To calculate the mass defect, we use the equation:

$\Delta m=\text{Mass of reactants}-\text{Mass of products}$

Putting values in above equation, we get:

$\Delta m=(39.963998-39.962591)=0.001407u$

To calculate the energy released, we use the equation:

$E=\Delta mc^2\\E=(0.001407u)\times c^2$

$E=(0.001407u)\times (931.5MeV)$ (Conversion factor: $1u=931.5MeV/c^2$ )

$E=1.3106MeV$

Hence, the energy released in the given nuclear reaction is 1.3106 MeV.

6 0

3 years ago

How many grams of iron(III) oxide would be required to make 187 g of iron

enyata [817]

Answer:267 g

Explanation:

4 0

3 years ago