How many milliliters of 0.100 m naoh are required to neutralize 9.00 ml of 0.0500 m hcl?

1 answer:

6 0

V ( NaOH ) = mL ?

M ( NaOH ) = 0.100 M

V ( HCl ) = 9.00 mL / 1000 => 0.009 L

M ( HCl ) = 0.0500 M

number of moles HCl:

n = M x V

n = 0.009 x 0.0500 => 0.00045 moles HCl

mole ratio:

<span>HCl + NaOH = NaCl + H2O
</span>
1 mole HCl ---------------- 1 mole NaOH
0.00045 moles HCl ----- ??

0.00045 x 1 / 1 => 0.00045 moles of NaOH

M = n / V

0.100 = 0.00045 / V

V = 0.00045 / 0.100

V = 0.0045 L

1 L ------------ 1000 mL
0.0045 L ----- ??

0.0045 x 1000 / 1 => 4.5 mL of NaOH

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A solution has a volume of 375 ml and contains 12.6 moles of NaCI what is it molarity

miskamm [114]

Answer:

M = 33.6M .

Explanation:

Hello there!

In this case, according to the definition of molarity which is computed by dividing the moles of solute by the liters of solution, it is possible to realize that the moles of the solute are 12.6 mol and the liters of solution are 375/1000= 0.375 L and therefore the molarity of the solution can be calculated as follows:

$M=\frac{12.6mol}{0.375L}\\\\M=33.6M$