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Veronika [31]
1 year ago
15

The box in Fig (a) has a mass m and travels down the smooth circular ramp such that when it i..the angle θ it has a speed v Dete

rmine its angular momentum about point O at this instant and the rate of increase in its speed, i.e., a How to solve using only kinematic equations? 
Physics
1 answer:
koban [17]1 year ago
3 0

Angular momentum about point O at this instant and the rate of increase in its speed using only kinematic equations is a= gsinθ.

Angular momentum =I.W

=mr²*V/r

Angular momentum=mvr

F=ma

mgsinθ=m.a

a=gsinθ

The kinematic equations are a collection of equations that explain the motion of an object with constant acceleration. Kinematics is a branch of physics that originated in classical mechanics and describes the motion of points, bodies, and systems of things without taking the forces that propel them. Kinematics is the study of the motion of mechanical objects, bodies, and systems without consideration of their related physical qualities and the forces acting on them. Kinematics equations need understanding of derivatives, rate of change, and integrals. The discipline, often known as the geometry of motion, employs algebra to mathematically represent these movements.

Learn more about Angular momentum here:

brainly.com/question/15104254

#SPJ4

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Answer:

Without plants producing oxygen, no creatures would be able to breath and would thus die off. With no creatures breathing, and thus producing no carbon dioxide, plants would starve off and die since they require carbon dioxide to live.

Explanation:

4 0
3 years ago
Please help i don't understand
IrinaVladis [17]
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Please round 1045.2 to three significant digits
Anton [14]

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3 years ago
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When monochromatic light shines perpendicularly on a soap film (n = 1.33) with air on each side, the second smallest nonzero fil
Anika [276]

Let us start from considering monochromatic light as an incidence on the film of a thickness t whose material has an index of refraction n determined by their respective properties.

From this point of view part of the light will be reflated and the other will be transmitted to the thin film. That additional distance traveled by the ray that was reflected from the bottom will be twice the thickness of the thin film at the point where the light strikes. Therefore, this relation of phase differences and additional distance can be expressed mathematically as

2t + \frac{1}{2} \lambda_{film} = (m+\frac{1}{2})\lambda_{film}

We are given the second smallest nonzero thickness at which destructive interference occurs.

This corresponds to, m = 2, therefore

2t = 2\lambda_{film}

t = \lambda_{film}

The index of refraction of soap is given, then

\lambda_{film} = \frac{\lambda_{vacuum}}{n}

Combining the results of all steps we get

t = \frac{\lambda_{vacuum}}{n}

Rearranging, we find

\lambda_{vacuum} = tn

\lambda_{vacuum} = (278)(1.33)

\lambda_{vacuum} = 369.74nm

4 0
3 years ago
The critical angle for water is 49°. If a ray of light
Sonja [21]

Answer:

Snell's Law states

Ni sin i = Nr sin r

Judging from the question the source of the ray is in the water (directed up)

or NI = 1 / sin 49      Ni = 1.325 deg     the critical angle

From inside the pond:

Nr = 1.325 * sin 45 / 1 = 94 deg  

So refraction can occur  outside the pond and you do not have total internal refection.

 

3 0
3 years ago
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