Answer:
Distance of the point where electric filed is 2.45 N/C is 1.06 m
Explanation:
We have given charge per unit length, that is liner charge density 
Electric field E = 2.45 N/C
We have to find the distance at which electric field is 2.45 N/C
We know that electric field due to linear charge is equal to
, here
is linear charge density and r is distance of the point where we have to find the electric field
So 
r = 1.06 m
So distance of the point where electric filed is 2.45 N/C is 1.06 m
Answer:

Explanation:
We can calculate the acceleration experimented by the passenger using the formula
, taking the initial direction of movement as the positive direction and considering it comes to a rest:

Then we use Newton's 2nd Law to calculate the force the passenger of mass m experimented to have this acceleration:

Which for our values is:

Answer:


Explanation:
v = Velocity of the elevator = 3.1 m/s
= Angle of the slope = 
Vertical component is given by

The vertical component of the velocity is
.
Horizontal component is given by

The horizontal component of the velocity is
.