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crimeas [40]
3 years ago
12

A tennis ball, a bowling ball, and a feather are dropped from the top of a tall building at the same time. Consider what you hav

e learned about air resistance. Which object reaches the ground first?
Physics
2 answers:
seropon [69]3 years ago
7 0
The bowling ball would reach the ground first because it has a higher density.
Yuri [45]3 years ago
3 0
Bowling ball reaches the ground first
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Janelle stands on a balcony, two stories above Michael. She throws one ball straight up and one ball straight down, but both wit
antoniya [11.8K]

Answer:

Both balls have the same speed.

Explanation:

Janelle throws the two balls from the same height, with the same speed. Both balls will have the same potential and kinetic energy. Energy must be conserved. When the balls pass Michael, again they must have the same potential and kinetic energy.

4 0
3 years ago
The skillful and effective interaction of movements; completing more than one movement at a time
horrorfan [7]
It is called balance
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3 years ago
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With what force will a car hit a tree if the car has a mass of 3,415 kg and it is accelerating at
weeeeeb [17]

Answer:

F= 17,075\ N

Explanation:

When the car is under an accelerating force and hits a tree, the instant force received by the tree is the same force that is accelerating the car.

The accelerating force can be calculated using Newton's second law:

F=m\cdot a

Where m is the mass of the car and a is the acceleration.

F=3,415\ kg\cdot 5\ m/s^2

\boxed{F= 17,075\ N}

3 0
3 years ago
A gun is fired on a day when the speed of sound is 335 m/s and an echo is heard 0.75 seconds later. How far away is the object t
cricket20 [7]

Answer:

v= 335 m/s

2∆t= 0.75 s

∆x= v.∆t → ∆x= 335×½×0.75 = 125.625 m

8 0
2 years ago
A force of 6.00 N acts in the positive direction on a 3.00 kg object, originally traveling at +15.0 m/s, for 10.0 s. (a) What is
frozen [14]

Answer:

60 kg m/s

Explanation:

Let a\;\; m/s^2 be the acceleration of the object.

As the acceleration of the object is constant, so

a=\frac {v-u}{t}\cdots(i)

Given that applied force, F=6.00 N,

From Newton's second law, we have

F= m\times a,

\Rightarrow F=\frac {m(v-u)}{t} [from equation (i)]

\Rightarrow Ft=m(v-u)

\Rightarrow Ft=mv-mu

\Rightarrow mv-mu=6\times 10 [given that time, t=10 s and F=6 N]

\Rightarrow mv-mu=60 kg \;m/s

Here mv is the final momentum of the object and mu is the initial momentum of the object.

So, the change in the momentum of the object is mv-mu.

Hence, the change in the momentum of the object is 60 kg m/s.

6 0
3 years ago
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