<h3>
Answer:</h3>
-271.96 °C
<h3>
Explanation:</h3>
<u>We are given;</u>
- Volume of the tank as 0.0625 L
- Mass of nitrogen gas as 0.0925 kg or 92.5 g
- Pressure of the gas as 5.17 atm
we are required to calculate the temperature of the gas.
<h3>Step 1: Calculate the number of moles of nitrogen gas </h3>
Moles = Mass ÷ Molar mass
Molar mass of nitrogen gas = 28.0 g/mol
Therefore;
Moles of N₂ = 92.5 g ÷ 28.0 g/mol
= 3.304 moles
<h3>Step 2: Calculate the temperature of the gas;</h3>
According to the ideal gas equation;
PV = nRT , where n is the number of moles and R is the ideal gas constant, 0.082057 L.atm/mol.K
Rearranging the formula;
T = PV ÷ nR
= ( 5.17 atm × 0.0625 L) ÷ (3.304 moles × 0.082057)
= 1.19 K
But, °C = K - 273.15
Therefore;
T = 1.19 K - 273.15
= -271.96 °C
Thus, the temperature of the gas will be -271.96 °C
