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3 years ago

Is a mirror transparent, translucent or opaque?

Physics

2 answers:

My name is Ann [436]3 years ago

5 0

Opaque, if we are talking about a one-way mirror ;)

mr Goodwill [35]3 years ago

4 0

A mirror is OPAQUE........

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Although the evidence is weak, there has been a concern in recent years over possible health effects from the magnetic fields ge

sergey [27]

Answer:

The magnetic field strength is $B = 2 \mu T$

Explanation:

From the question we are told that

The length line above the ground is $R = 20m$

The current of the line is $I = 200A$

The voltage of the line is $V = 110kV$

Generally magnetic field strength is mathematically represented as

$B = \frac{\mu_o I}{2 \pi R}$

Where $\mu_0$ is the permeability of free space $= 4\pi * 10^{-7} N/A^2$

$B = \frac{(4\pi * 10^{-7} N/A^2) *200}{2 \pi *20}$

$= (2.0*10^{-7})[\frac{200}{20} ]$

$= 2*10^{-6}T$

$= 2 \mu T$

Earths magnetic field is approximately given as $50 \mu T$

So the percentage would be

$= \frac{Magnetic \ Field \ Intensity \ Of \ Line}{Earth's \ Magnetic \ Field} * 100$

$= \frac{2 \mu T }{50 \mu T } * 100$

$=4$ %

7 0

3 years ago

A rock is thrown straight upward off the edge of a balcony that is 5 m above the ground. The rock rises 10 m, then falls all the

Dvinal [7]

Displacement = distance and direction from the start-point
to the end-point, regardless of the route followed on the way.

From the throw to the 'plop', the displacement is 5 meters down.

7 0

3 years ago

What are the best units for DENSITY of a solid like a rock or a lemon? *

Ulleksa [173]

You would use answer 2O g/cm3

4 0

3 years ago

Help in physics please :(((

Arlecino [84]

Answer:

I am sorry I can't draw graphical ok how to draw the graph where what is your position the displacement of time and work 7 kilometres east in 2 hours and what will happen to the time and 72 in 1 hour what is the displacement you after take the displacement formula that is total time taken divided by the distance travelled ok displacement and distance travelled is different about its terms ok

8 0

3 years ago

Several large firecrackers are inserted into the holes of a bowling ball, and the 6.3 kg ball is then launched into the air with

Anni [7]

Answer

given,

mass of the ball = 6.3 kg

speed of the ball = 10.4 m/s

angle made with horizontal = 43°

m_a = 1.8 kg v_a = 2.2 m/s

m_b = 1.6 kg v_b = 1.8 m/s

mass of third particle = 6.3 - 1.8 - 1.6

= 2.9 kg

u cos θ = 10.4 x cos 43° = 7.61 m/s

by using conservation momentum along x-axis

6.3 x 7.61 = 1.8 × (-2.2) + 0 + 1.6 × V₃ₓ

V₃ₓ = 32.44 m/s (toward right)

by using conservation momentum along y-axis

0 = 0 + 1.6 x 1.8 + 1.6 × V₃y

V₃y = -1.8 m/s (indicate downward)

velocity of the third particle

$v = \sqrt{32.44^2 + (-1.8)^2}$

v = 32.49 m/s

$tan \theta = \dfrac{-1.8}{32.44}$

$\theta = tan^{-1}(\dfrac{-1.8}{32.44})$

θ = 3.176° (downward with horizontal)

4 0

3 years ago