Answer:
EMF induced in the loop is 9.4 V
Explanation:
As we know that initial magnetic flux of the loop is given as
As soon as the area of the loop becomes zero the final magnetic flux of the loop is ZERO
Now as per faraday's law of electromagnetic induction the EMF is induced due to rate of change in magnetic flux
so we will have
so we will have
Answer:
Explanation:
a ) It is given that bomb was at rest initially , so , its momentum before the explosion was zero.
b ) We shall apply law of conservation of momentum along x and y direction separately because no external force acts on the bomb.
If v be the velocity of the third part along a direction making angle θ
with x axis ,
x component of v = vcosθ
So momentum along x axis after explosion of third part = mv cosθ
= 10 v cosθ
Momentum along x of first part = - 5 x 42 m/s
momentum of second part along x direction =0
total momentum along x direction before explosion = total momentum along x direction after explosion
0 = - 5 x 42 + 10 v cosθ
v cosθ = 21
Similarly
total momentum along y direction before explosion = total momentum along y direction after explosion
0 = - 5 x 38 + 10 v sinθ
v sinθ= 21
squaring and and then adding the above equation
v² cos²θ +v² sin²θ = 21² +19²
v² = 441 + 361
v = 28.31 m/s
Tanθ = 21 / 19
θ = 48°
Total force = Frope - mg = 309-300
total force = ma
9 = 30a
Answer:
200 N
Explanation:
Power = work / time
Work = force × distance
Therefore:
Power = force × distance / time
100 W = F × 10 m / 20 s
F = 200 N
He exerted 200 N.
