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brilliants [131]
3 years ago
13

Solve without using a calculator. on a cold day near the ocean, it was found that 8 g of an unknown gas occupies a volume that i

s a little less than 6 l. based on this information, what is the most likely identity of the unknown gas?
Physics
1 answer:
liberstina [14]3 years ago
7 0

Assuming that the gas acts like an ideal gas so that the molar volume is Vm = 22.4 L / moles, we can calculate for the number of moles.

number of moles = 6 L / (22.4 L / mol) = 0.2679 moles

 

So the molar mass of this gas is:

molar mass = 8 g / 0.2679 moles = 29.9 g/mol

 

The value is around 32 g/mol which is the molar mass of oxygen. Therefore the answer is:

<span>O2</span>

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a train travles at a speed of 30m/s. the train starts at an initial position of 1000 meters and travels for 30 seconds. what is
ycow [4]

Answer:

1900 meters

Explanation:

30m/s x 30 second = 900 meters

+ 1000 meters starting position

= 1900meters

5 0
3 years ago
Using monochromatic light of 410 nm wavelength, a single thin slit forms a diffraction pattern, with the first minimum at an ang
VLD [36.1K]

Answer:

c. 307 nm

Explanation:

angular position of first dark fringe =  λ / d ,   λ is wavelength and  d is width of slit .

(40 x π ) / 180 = 410 / d

angular position of second  dark fringe =  2 x λ / d ,   λ is wavelength and  d is width of slit .

(60 x π ) / 180 = 2 x λ / d

Dividing these equations

60 / 40 =  2 x λ / 410

λ = 307.5 nm.

5 0
4 years ago
HAaaaaaaaaaaaLPPP thank you.
lara31 [8.8K]
15 guesting i think it not right
7 0
3 years ago
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Sliding friction is affected by the weight of the object.<br><br> True or false
Dmitry [639]
Yes that is correct or in other form, True

7 0
3 years ago
Read 2 more answers
1) A train accelerates from 36 km/hr to 54 km/hr in 10<br> s. Find acceleration?
Crank

Answer: Given:

Initial velocity= 36km/h=36x5/18=10m/s

Final velocity =54km/h=54x5/18=15m/s

Time =10sec

Acceleration = v-u/ t

=15-10/10=5/10=1/2=0.5 m/s2

Distance =s=?

From second equation of motion:

S=ut +1/2 at^2

=10*10+1/2*0.5*10*10

=100+25

=125m

So distance travelled 125m

Hope it helps you

3 0
3 years ago
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