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kotegsom [21]
2 years ago
8

Why is oxygen more chemically reactive than nitrogen?

Physics
2 answers:
grin007 [14]2 years ago
5 0

Answer:

O2 has two more electrons compared to N2, with extra 2 electrons in the higher energy anti-bonding orbitals known as Diradical. These electrons have higher energy and are unpaired; therefore, O2 is more reactive

Explanation:

Anni [7]2 years ago
5 0

Answer:

O B. Oxygen needs to gain only 2 electrons to have a full octet, while nitrogen needs to gain 3.

Explanation:

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3 years ago
One circuit contains only an ac generator and a resistor, and the rms current in this circuit is IR. Another circuit contains on
snow_tiger [21]

Answer:

1/3 times.

Explanation:

Let V₀ be the peak voltage .

IR ( rms )  = ( V₀ / √2 R )

R is value of resistance

IC =  ( V₀ ωC / √2  )

( 1 / ωC is reactance of capacitance in ac circuit  )

\frac{I_R}{I_C} =\frac{\frac{V_0}{\sqrt{2}R } }{\frac{V_0\omega C}{\sqrt{2} } }

= \frac{I_R}{I_C} = \frac{1}{\omega C R}

When frequency is tripled angular frequency will also be tripled

hence the ratio \frac{I_R}{I_C} becomes 1/3 times.

7 0
3 years ago
A positive charge is moving across a room from south to
slega [8]

Answer:toward the ceiling

Explanation:

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8 0
2 years ago
If the velocity and frequency of a wave are both doubled, how does the wavelength change?
Sindrei [870]

The wavelength will remain unchanged.

Explanation:

The velocity v of a wave in terms of its wavelength \lambda and frequency \nu is

v = \lambda\nu (1)

so if we double both the velocity and the frequency, the equation above becomes

2v = \lambda(2\nu) (2)

Solving for the wavelength from Eqn(2), we get

\lambda = \dfrac{2v}{2\nu} = \dfrac{v}{\nu}

We would have gotten the same result had we used Eqn(1) instead.

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Explanation:

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3 years ago
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