a block sliding on the ground where uk= 0.193 experiences a 14.7N friction force. what is the mass of the block in kg

erica [24]

Yes the relationship between them is direct linear ..

4 0

3 years ago

A moving rope (parallel to the slope) is used to pull skiers up the mountain. If the slope of the hill is 37" and friction is ne

Charra [1.4K]

Since rope is parallel to the inclined plane so here we can say that net force parallel to the person which is pulling upwards must counterbalance the component of weight of the person.

Now here we will do the components of the weight of the person

given that weight of the person = 500 N

now its components are

$W_x = 500 cos37$

$W_y = 500 sin37$

now here as we can say that one of the component is balanced here by the normal force perpendicular to plane

while the other component of the weight is balanced by the force applied on the rope

So here the force applied on the rope will be given as

$F = W_y = 500 sin37$

$F = 300 N$

so it apply 300 N force along the inclined plane

5 0

4 years ago

What should a sailboat operator do when approaching a PWC head-on

nekit [7.7K]

In accordance with the International Regulation for the prevention of collisions at sea:

1.- A sailing boat has a passing preference over a motorized boat, except when the motor boat is limited by its draft.

2.- The sailboat must maintain its course and speed.

3.- If it is evident that the PWC does not respond, the sailboat must sound the warning signal, and change its course to starboard.

4.- All actions must be taken as soon as possible.

5.- If a sailboat is using its engine, the situation changes, and in that case, both ships must alter to starboard.

8 0

3 years ago

A uniform steel girder of weight 22KN and of length 12m is lifted off the ground at one end by means of a crane. When the raised

Keith_Richards [23]

Answer:

Explanation:

For free body diagram see attached sheet .

W is weight of steel girder acting at the middle point of its length . T is tension in the cable .

OB = √ ( 12² - 2² )

= 11.83 m .

OC = 11.83 / 2 = 5.915 m

Taking moment of tension T and weight W about point O

W x OC = T x OB

22 x 5.915 = T x 11.83

T = 22 x 5.915 / 11.83

= 11 kN

Considering forces acting in vertical direction and equating forces in opposite direction

T + R = W

R = W - T

= 22 - 11 = 11 KN

So force of grinder on the ground = R

= 11 KN.

8 0

3 years ago

In a golf ball game, a person hits the golf ball with a club. The club is in contact with the ball, which is initially at rest,

Anon25 [30]

Answer:

F=4040.81 N

Explanation:

Given that

Time ,t= 2.45 ms

Mass ,m= 0.055 kg

v= 1.8 x 10² m/s = 180 m/s

We know that rate of change in the linear momentum is known as force.

Momentum P = m v

$F=\dfrac{dP}{dt}$

Therefore force F

$F=\dfrac{\Delta P}{\Delta t}$

$F=\dfrac{0.055\times 180}{2.45\times 10^{-3}}\ N$

F=4040.81 N

Therefore force on the ball will be 4040.81 N

6 0

3 years ago