How do nerves tie the other parts of the nervous system together?

How much kinetic energy a spring that streches 4m would be?

miv72 [106K]

Answer:

Explanation:bjbhfcvvjkkknbnnnm

8 0

2 years ago

List two methods by which a community can save water. In your own words, explain how these methods would help to increase the ye

Oliga [24]

Conservation and Rain Water Tank. Through conservation, they can save water in their own houses by lessening the use of water in an unimportant purpose; they can turn of the faucet when it is not used; they can use their laundry water to clean the bathroom and there are more. Through Rain Water Tank, they can create this structure in order to collect rain water and store it in the tank then use it afterwards such as in watering the plants.

8 0

3 years ago

A single Oreo cookie provides 53 kcal of energy. An athlete does an exercise that involves repeatedly lifting (without accelerat

Sever21 [200]

Answer:

Approximately $325$ (rounded down,) assuming that $g = 9.81\; {\rm N \cdot kg^{-1}}$ .

The number of repetitions would increase if efficiency increases.

Explanation:

Ensure that all quantities involved are in standard units:

Energy from the cookie (should be in joules, ${\rm J}$ ):

$\begin{aligned} & 53\; {\rm kCal} \times \frac{1\; {\rm kJ}}{4.184\; {\rm kCal}} \times \frac{1000\; {\rm J}}{1\; {\rm kJ}} \approx 2.551 \times 10^{5}\; {\rm J} \end{aligned}$ .

Height of the weight (should be in meters, ${\rm m}$ ):

$\begin{aligned} h &= 2\; {\rm dm} \times \frac{1\; {\rm m}}{10\; {\rm dm}} = 0.2\; {\rm m}\end{aligned}$ .

Energy required to lift the weight by $\Delta h = 0.2\; {\rm m}$ without acceleration:

$\begin{aligned} W &= m\, g\, \Delta h \\ &= 100\; {\rm kg} \times 9.81\; {\rm N \cdot kg^{-1}} \times 0.2\; {\rm m} \\ &= 196\; {\rm N \cdot m} \\ &= 196\; {\rm J} \end{aligned}$ .

At an efficiency of $0.25$ , the actual amount of energy required to raise this weight to that height would be:

$\begin{aligned} \text{Energy Input} &= \frac{\text{Useful Work Output}}{\text{Efficiency}} \\ &= \frac{196\; {\rm J}}{0.25} \\ &=784\; {\rm J}\end{aligned}$ .

Divide $2.551 \times 10^{5}\; {\rm J}$ by $784\; {\rm J}$ to find the number of times this weight could be lifted up within that energy budget:

$\begin{aligned} \frac{2.551 \times 10^{5}\; {\rm J}}{784\; {\rm J}} &\approx 325 \end{aligned}$ .

Increasing the efficiency (the denominator) would reduce the amount of energy input required to achieve the same amount of useful work. Thus, the same energy budget would allow this weight to be lifted up for more times.

4 0

1 year ago

PLZZZZZZZZZ HELPPPPP. BRAINLEST GIVEN What is a force of attraction between an object and the earth due to gravity?

kotykmax [81]

Answer:

acceleration due to gravity: -9.8 m/s^2

Fg=mass of object*(-9.8)

Explanation:

This is a pretty vague question, but I'll answer as best I can.

All matter has gravity. YOU have gravity, although your gravitational pull is small. So, the force of attraction between the Earth and an object on Earth is modeled as

Force of gravity=(Gravitational constant*mass of object 1*mass of object 2)/distance between objects squared

Note that distance between an object on Earth and Earth is the radius of Earth (distance to Earth's core/center of mass)

6 0

2 years ago

Answer True or False to each case. Coulomb's law states that the force between static charges Q1 and Q2 is K Q1Q2/r2 where K is

Julli [10]

Explanation:

The Coulomb's law states that the force acting on two charges is directly proportional to the product of charges and inversely proportional to the square of distance between them . Mathematically, it is given by

$F=k\dfrac{q_1q_2}{r^2}$

Where

k is the electrostatic constant

q₁ and q₂ are charges

r is the distance between them.

The SI unit of electric force is Newton. It can be attractive or repulsive. The attraction or repulsion depend on charges. If both charges are positive, the force is repulsive and if both are opposite charges, the force is attractive.

4 0

2 years ago