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aivan3 [116]
3 years ago
6

a 2-kg metal ball moving at a speed of 3 m/s strikes a 1-kg wooden ball that is at rest. after the collision, the speed of the m

etal ball is 1 m/s. Assuming momentum is conserved, what is the speed of the wooden ball
Physics
1 answer:
tresset_1 [31]3 years ago
5 0
M1u1 + m2u2 = m1v1 + m2v2
2 * 3 + 1 * 0 = 2 * 1 + 1 * v2
6 = 2 + v2
v2 = 6 - 2 = 4 m/s.

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A 1000-kg whale swims horizontally to the right at a speed of 6.0 m/s. It suddenly collides directly with a stationary seal of m
anzhelika [568]

Answer:

Momentum after collision will be 6000 kgm/sec

Explanation:

We have given mass of the whale = 1000

Initial velocity v = 6 m/sec

It collides with other mass of 200 kg which is at stationary

Initial momentum of the whale = 1000×6 = 6000 kgm/sec

We have to find the momentum after collision

From conservation of momentum

Initial momentum = final momentum

So final momentum = 6000 kgm/sec

5 0
3 years ago
Evaluate u+xy where U=3 X=4 Y=7
Reptile [31]

Answer:

31

Explanation:

Given:

U=3

X=4

Y=7

u + xy

Substitute the given values to the equation:

3 + (4)(7)

3 + 28

31

6 0
3 years ago
The smallest separation resolvable by a microscope is of the order of magnitude of the wavelength used. What energy electrons wo
hjlf

Answer: a) for 150 Angstroms 6.63 *10^-3 eV; b) for 5 Angstroms 6.02 eV

Explanation: To solve this problem we have to use the relationship given by De Broglie as:

λ =p/h where p is the momentum and h the Planck constant

if we consider the energy given by acceleration tube for the electrons given by: E: e ΔV so is equal to kinetic energy of electrons p^2/2m

Finally we have:

eΔV=p^2/2m= h^2/(2*m*λ^2)

replacing we obtained the above values.

6 0
3 years ago
A device consisting of four heavy balls connected by low-mass rods is free to rotate about an axle. It is initially not spinning
zubka84 [21]

The angular speed of the device is 1.03 rad/s.

<h3>What is the conservation of angular momentum?</h3>

A spinning system's ability to conserve angular momentum ensures that its spin will not change until it is subjected to an external torque; to put it another way, the rotation's speed will not change as long as the net torque is zero.

Using the conservation of angular momentum

L_{i}=L_{f}

Here,  = the system's angular momentum before the collision

L_{i} = 0 + mv

= (0.005)(450)(0.752)

= 1.692 kgm²/s

The moment of inertia of the system is given by

I = 2(M₁R₁² + M₂R₂²)+ mR₁²

= 2[(1.2)(0.8)² +(0.5)(0.3)²]+0.005(0.8)²

= 1.6292 kgm²

Here,  = Iω

So,

1.692 = 1.6292(ω)

ω = 1.03 rad/s

To know more about the conservation of angular momentum, visit:

brainly.com/question/1597483

#SPJ1

4 0
1 year ago
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what's the question here?

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3 years ago
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