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Arada [10]
2 years ago
7

I really need help on this problem for chemistry, please help!

Chemistry
1 answer:
katrin2010 [14]2 years ago
8 0

answer and explanation

we are given the balanced reaction and so we begin by calculating the number of mols of each reactant

for Al

mols = mass/Molar mass

= 22.0g / 26.98g/mol

= 0.82 mols

for oxygen

mols = mass / Molar mass

= 26.0g / 16.00g/mol

= 1.6 mols

theerefore

a. the limiting reagent is Al

b. theoretical yield will be determine using the limiting reagent.

from the balanced reaction we see that the mol ratio between aluminum and aluminum oxide is 4:2

therefore

2/4 x0.82 = 0.41 mols of aluminum oxide will form

the mass will be

mass = n x M

= 0.41 mols x 101.96g/mol

= 41.8 grams

c. percentage yield is:

actual yield/ theorectical yield x 100

= 40.0/41.8 x 100%

= 95.7 %

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