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1 year ago

8

It is possible to use a simple machine and gain no mechanical advantage

1 answer:

nignag [31]1 year ago

4 0

Answer:

yes

Explanation:

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In a series circuit, when you add more resistance, what will happen to the amount of current?

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The amount of current will increase since they are inversely proportional

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4 years ago

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What weight of water is displaced by a 100-ton floating ship? What is the buoyant force that acts on this ship?

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I can never remember whether the '100 T' is the gross weight of the ship or the weight of the cargo it can carry. Let's say it's the gross loaded weight. / / / A 100 ton floating ship displaces 100 tons of water, and the bbuoyant force on it is 100 tons.

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3 years ago

An 8000-kg engine pulls a 40,000 kg train along a level track and gives it an acceleration a1 = 1.20 m/s 2 . What acceleration (

mel-nik [20]

a = F/(m1+m2)
1.2 = F/48,000
F = 57,600N

a = F/(m1+m3)
a = 57,600/24,000
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4 years ago

The water stream strikes the inclined surface of the cart. Determine the power produced by the stream if, due to rolling frictio

levacccp [35]

Answer

given,

constant speed of cart on right side = 2 m/s

diameter of nozzle = 50 mm = 0.05 m

discharge flow through nozzle = 0.04 m³

One-fourth of the discharge flows down the incline

three-fourths flows up the incline

Power = ?

Normal force i.e. Fn acting on the cart

$F_n = \rho A (v - u)^2 sin \theta$

v is the velocity of jet

Q = A V

$v = \dfrac{0.04}{\dfrac{\pi}{4}d^2}$

$v= \dfrac{0.04}{\dfrac{\pi}{4}\times 0.05^2}$

v = 20.37 m/s

u be the speed of cart assuming it to be u = 2 m/s

angle angle of inclination be 60°

now,

$F_n = 1000 \times \dfrac{\pi}{4}\times 0.05^2\times (20.37 - 2)^2 sin 60^0$

F n = 2295 N

now force along x direction

$F_x = F_n sin 60^0$

$F_x = 2295 \times sin 60^0$

$F_x = 1987.52\ N$

Power of the cart

P = F x v

P = 1987.52 x 20.37

P = 40485 watt

P = 40.5 kW

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4 years ago

A crane lifts up two boxes.<br><br> Which free body diagram shows the forces acting on block A?

Temka [501]

Answer:

The 3rd graph

Explanation:

A free body diagram is a diagram which shows all the forces acting on an object.

The problem asks us to find the free body diagram of block A, so we must find all the forces acting on block A.

We have 3 forces acting on block A in total:

- The force of gravity (its weight), which pushes the block downward (in the diagram, it is the force represented with $F_{gA}$

- The tension in the rope 1, which pulls block A upwards: this force is represented with $F_{T1}$

- The tension in the rope 2, due to the weight of block 2, which pulls block A downwards: this force is represented with $F_{T2}$

Based on the direction of these 3 forces, the correct diagram is the 3rd one.

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3 years ago

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