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Paha777 [63]
4 years ago
12

An 8000-kg engine pulls a 40,000 kg train along a level track and gives it an acceleration a1 = 1.20 m/s 2 . What acceleration (

a2) would the engine give to a 16,000-kg train?
Physics
1 answer:
mel-nik [20]4 years ago
8 0

a = F/(m1+m2)
1.2 = F/48,000
F = 57,600N

a = F/(m1+m3)
a = 57,600/24,000
a = 2.4 m/s^2
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ListenA person weighing 6.0 × 102 newtons rides an elevator upward at an average speed of 3.0 meters per second for 5.0 seconds.
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Answer:

(d) 9 × 10^{3] J

Explanation:

from the question we are given the following:

weight of the man = 6.0 × 10 ^ {2} N

average speed (v) = 3 m/s

time (t) = 3 s

potential energy (U) = ?

We can calculate the increase in potential energy of the man by applying the formula below

increase in potential energy = P₂ - P₁

where

  • P₁ is the initial potential energy
  • P₂ is the final potential energy
  • Potential energy = mass x acceleration due to gravity x height

From physic we know that weight = mass x acceleration due to gravity

  • We should take note that the distance in this case is also our height, and we can get it from the formula distance = velocity x time
  • Distance = 3 x 5 = 15 meters
  • Initial potential energy P₁ is zero because the person was initially in motion and potential energy is the energy at rest.

therefore

potential energy = 6.0 × 10 ^ {2} × 15 = 9 × 10^{3] J

4 0
4 years ago
An object that is dropped from a height H falls with a constant acceleration of g. The final
GuDViN [60]

The height need to change by 4 to double the final velocity.

<h3>Final velocity of the object</h3>

The final velocity of an object during a free fall is related to maximum height of fall as given the equation below.

v = √2gh

v² = 2gh

v²/h = 2g

v₁²/h₁ = v₂²/h₂

when v₂ = 2v₁, change in height is calculated as;

h₂ = h₁v₂²/v₁²

h₂ = (h₁ (2v₁)²) / (v₁)²

h₂ = 4h₁v₁² / v₁²

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Thus, the height need to change by 4 to double the final velocity.

Learn more about final velocity here: brainly.com/question/25905661

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4 0
2 years ago
A positive charge is placed within the sphere without touching it. You grounded the sphere by touching it with your finger. Then
zhuklara [117]

Answer:

Negative

Explanation:

If a negatively charged object is used to charge a neutral object by induction, then the neutral object will acquire a positive charge. And if a positively charged object is used to charge a neutral object by induction, then the neutral object will acquire a negative charge:

We have a neutral sphere

1) Electrons are attracted to the positive charge

2) Electrons enter the sphere from ground, attrated to the + charge in the sphere

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3 0
4 years ago
A cannon ball is shot horizontally off a 37.0 m cliff and lands a distance of 18.5 m
4vir4ik [10]

Answer:

vₓ = 6.73 m/s

Explanation:

  • Assuming no other external influences than gravity, in the horizontal direction (which we make to coincide with the x- axis) , speed is constant, so, applying the definition of average velocity, we can write the following equation:

       v_{x} = \frac{\Delta x}{\Delta t} (1)

  • Now, in the vertical direction (coincident with the y- axis) , as both movements are independent each other, initial velocity is zero, so we can write the following equation for the vertical displacement:

       \Delta h = \frac{1}{2} * g * t^{2} (2)

  • where Δh = -37.0 m , g = -9.8 m/s2
  • Solving (2) for t, we get:

       t = \sqrt{\frac{2*\Delta h}{g} } =\sqrt{\frac{2*37.0m}{9.8m/s2}} = 2.75 s (3)    

  • Taking t₀ = 0, ⇒ Δt = t
  • Replacing (3) in (1), we get:

       v_{x} = \frac{\Delta x}{\Delta t} = \frac{x}{t}  = \frac{18.5m}{2.75s} = 6.73 m/s

  • As the horizontal velocity is constant, the initial horizontal velocity is just the average one, i.e., 6.73 m/s.
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3 years ago
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