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4 years ago

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An 8000-kg engine pulls a 40,000 kg train along a level track and gives it an acceleration a1 = 1.20 m/s 2 . What acceleration (

a2) would the engine give to a 16,000-kg train?

1 answer:

mel-nik [20]4 years ago

8 0

a = F/(m1+m2)
1.2 = F/48,000
F = 57,600N

a = F/(m1+m3)
a = 57,600/24,000
a = 2.4 m/s^2

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A tennis ball with a speed of 25.9 m/s is moving perpendicular to a wall. After striking the wall,

mihalych1998 [28]

Answer:

$-3550.1 m/s^2$

Explanation:

The initial velocity of the ball is

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while the final velocity of the ball is

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The time taken for the change in velocity to occur is

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The acceleration can be calculated as the change in velocity divided by the time taken:

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This is an example of inertia - the body keeps it's energy because there is no force applied to it. When we try to stop it's motion, it resists. A man is not rigidly attached to the bus, so he keeps moving forward, at least until he hits the front window from inside. Answer is D.

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3 years ago

Water drops fall from the edge of a roof at a steady rate. a fifth drop starts to fall just as the first drop hits the ground. a

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The height of the roof is <u>3.57m</u>

Let the drops fall at a rate of 1 drop per t seconds. The first drop takes 5t seconds to reach the ground. The second drop takes 4t seconds to reach the bottom of the 1.00 m window, while the 3rd drop takes 3t s to reach the top of the window.

Calculate the distances traveled by the second and the third drops s₂ and s₃, which start from rest from the roof of the building.

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The length of the window s is given by,

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The first drop is at the bottom and it takes 5t seconds to reach down.

The height of the roof h is the distance traveled by the first drop and is given by,

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