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horsena [70]
3 years ago
9

Students hypothesized that by running an electric current through the wire of the apparatus shown here, they could cause a non-m

agnetic nail to exhibit magnetic properties. What would be a reasonable way to test this?
a

Question 7 options:

a.Weigh the nail first while before turning the current on and again while the current was on.


b.Put the nail in water before turning the current on and again after turning the current off.


c.Examine the nail under a microscope before turning the current on and again after turning the current off.


d.See if iron filings will stick to the nail before turning the current on and again while the current was on.
Physics
2 answers:
astra-53 [7]3 years ago
5 0
The answer is d i think
Ivenika [448]3 years ago
5 0

The answer is D i think because i got it right!

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A textbook of mass 2.05 kg rests on a frictionless, horizontal surface. A cord attached to the book passes over a pulley whose d
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Answer:

a. 7.38 N b. 40.87 N c. 0.113 kg-m²

Explanation:

a. Let T be the tension in the cord. For the textbook, T = ma since no other force acts on it and it is an horizontal force, and m = mass = 2.05 kg and a = acceleration. We find the acceleration from s = ut + 1/2at² where u = initial speed = 0 (since it starts from rest),  s = distance moved = 1.30 m and t = time = 0.850 s.

Substituting these values into s,

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Substituting this into T, we have

T = ma = 2.05 kg × 3.6 m/s² = 7.38 N

b.  Let T be the tension in the cord attached to the book. The book has the only vertical forces acting on it as the tension, T(acting upwards) and its weight mg (acting downwards). So the net force acting on it is

T - mg = ma

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substituting a = 3.6 m/s² and g = 9.8 m/s² and m = 3.05 kg

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c. Since the tangential acceleration of the pulley is also the acceleration of the masses, the a = rα where r = radius of pulley = 0.200 m/2 = 0.100 m and α = angular acceleration of the pulley.

α = a/r = 3.6 m/s² ÷ 0.100 m = 36 rad/s²

Now, the torque on the pulley τ = Tr = Iα where I = moment of inertia of pulley about its rotational axis and T = tension in cord attached to book and r = radius of pulley = 0.200 m/2 = 0.100 m

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I = 40.87 N × 0.100 m ÷ 36 rad/s² = 0.113 kg-m²

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4 years ago
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Answer:

True

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