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Rainbow [258]
3 years ago
8

Suppose a shrimp has been put on the ground that has just been taken out of water.Now touch the shrimp from a distance by a stic

k.The shrimp will jump straight upward.Will the shrimp do any work in this case?
Physics
2 answers:
Alex777 [14]3 years ago
4 0

Answer:

yes

Explanation:

I would say yes because it's exerting some type of force as it reacts to the stick to make it jump straight in an upwards direction

Marizza181 [45]3 years ago
3 0
Yes, the shrimp does do some type of work because according to Newton's third law, every action has an equal yet opposite reaction force.
In this case, the stick is the action force and nudges/pokes the shrimp. The shrimp then reacts and exerts an opposite yet equal force by jumping in a straight, upwardly manner. So, yes the shrimp does do work in this case.

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Help please this is about the dialysis and things
AVprozaik [17]
1. B. Hemo is on a machine, peritoneal is in the abdomen
2. B. Nothing is as good as having your own kidney, and not everyone is a good candidate for all types of dialysis.
3. Also B. Peritoneal dialysis is done over a longer period of time, up to 24 hours. Hemodialysis is done in a few hours. Your kidney works 24/7.
8 0
3 years ago
Suppose students experiment with the tube and a variety of darts. Some darts have higher masses than others but are the same aer
san4es73 [151]

Answer:

The dart with the small mass will travel the farthest distance.

Explanation:

Acceleration is proportional to force times mass, and inertia is proportional to mass. Inertia is the reluctance of a moving body to stop, and a stationary body to start moving (inertia increses with mass). Assuming they both have the same aerodynamic design, and that they are both launched with the same force applied for the same time duration, the dart with less small mass will accelerate faster than the big mass dart. From this we can see that the small dart will have covered a longer distance before the effect of the force stops, when compared to the more massive dart.

5 0
3 years ago
2. A body is thrown vertically upward with a speed of 100 m/s.The time taken to be
Pachacha [2.7K]

Answer:

b. 20 sec

Explanation:

y = y₀ + v₀ t + ½ g t²

0 = 0 + (100) t + ½ (-10) t²

0 = 100t − 5t²

0 = t (100 − 5t)

t = 0, t = 20

The body lands after 20 seconds.

4 0
3 years ago
Consider a spherical volume of space that is large enough to be considered homogeneous. Also consider a particle on the surface
LenKa [72]

Answer:

Option A applies.

A.  Greater than its escape speed from the mass within the volume

Explanation:

Here it is mentioned that the spherical volume is large enough for the space to be considered as homogeneous. Also, the pressure within the volume is negligible, so that will not result into the re collapse of the Universe. Now as per our knowing, Hubble's Law relates the average speed of the particle to the distance R between the Earth and the particle. So, if the particle's speed is greater than it's escape speed from the mass within the volume, then the Universe is bound to re collapse back again. Option A applies.

3 0
3 years ago
A meter stick is held vertically with one end on the floor and is then allowed to fall. Find the speed of the other end when it
Tems11 [23]

Answer:

5.4 ms⁻¹

Explanation:

Here we have to use conservation of energy. Initially when the stick is held vertical, its center of mass is at some height above the ground, hence the stick has some gravitational potential energy. As the stick is allowed to fall, its rotates about one. gravitational potential energy of the stick gets converted into rotational kinetic energy.

L = length of the meter stick = 1 m

m = mass of the meter stick

w = angular speed of the meter stick as it hits the floor

v = speed of the other end of the stick

we know that, linear speed and angular speed are related as

v = r w\\w = \frac{v}{r}

h = height of center of mass of meter stick above the floor = \frac{L}{2} = \frac{1}{2} = 0.5 m

I = Moment of inertia of the stick about one end

For a stick, momentof inertia about one end has the formula as

I = \frac{mL^{2} }{3}

Using conservation of energy

Rotational kinetic energy of the stick = gravitational potential energy

(0.5) I w^{2} = mgh\\(0.5)(\frac{mL^{2} }{3}) (\frac{v}{L} )^{2} = mgh\\(0.5)(\frac{v^{2} }{3}) = gh\\(0.5)(\frac{v^{2} }{3}) = (9.8)(0.5)\\v = 5.4 ms^{-1}

7 0
3 years ago
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