Answer:



Explanation:
M = Mass of Uranus
G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²
r = Radius of Uranus = 25360 km
h = Altitude = 104000 km
= Radius of Miranda = 236 km
m = Mass of Miranda = 
Acceleration due to gravity is given by

The mass of Uranus is 
Acceleration is given by

Miranda's acceleration due to its orbital motion about Uranus is 
On Miranda

Acceleration due to Miranda's gravity at the surface of Miranda is 
No, both the objects will fall towards Uranus. Also, they are not stationary.
Waxing is when the moon gains more light that is visible to us from the sun and will eventually become a full moon which is when it looks like a pie and waining happens after the waxing process and eventually from our prospective will look like a banana
The snake and rat both share the same ancestor population that had a quadrate bone, which was inherited from an ancestor population.
<h3>What is a homo-logous structure?</h3>
A homo-logous structure is a trait that may or not have the same function but has a common evolutionary origin.
A homo-logous structure can be used to trace the evolutionary relationships between species.
Conversely, an analogous structure has the same function but it does not reflect an evolutionary origin.
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B.a homogeneous mixture
A solution is a homogeneous mixture of two or more substances. The amount of solute that can be dissolved in solvent is called its solubility.
By power transmitted by string, the frequency must be 163.31 Hz.
We need to know about power transmitted to solve this problem. The power transmitted by a wave on string can be determined by this equation
P = 1/2 . μ . ω² . A² . v
where P is the power, μ is mass per unit length of string, ω is angular speed, A is amplitude and v is wave propagation speed.
the wave propagation can be determined as
v = √(F.l/m)
where F is the string tension, l is length and m is the mass.
From the question above, we know that:
l = 2.7 m
m = 260 g = 0.26 kg
F = 36 N
A = 7.7 mm = 0.0077 m
P = 58 W
Find the mass per unit length
μ = m / l
μ = 0.26 / 2.7
μ = 0.096 kg / m
Find the wave propagation speed
v = √(F.l/m)
v = √(36. 2.7 /0.26)
v = √(373.85)
v = 19.34 m/s
Find the angular speed
P = 1/2 . μ . ω² . A² . v
58 = 1/2 . 0.096 . ω² . 0.0077² . 19.34
ω² = 1053777.29
ω = √1053777.29
ω = 1026.54 rad/s
Find the frequency
ω = 2πf
1026.54 = 2 . 3.14 . f
f = 163.31 Hz
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