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Aleonysh [2.5K]
3 years ago
8

Does a free falling object fall 2 meters in twice the time as it falls 1 meter?

Physics
1 answer:
KIM [24]3 years ago
3 0

A free-falling object has a consrant force acting on it . . .  the force of gravity, or what technical experts refer to as its "weight".

Since the object has a constant force acting on it, it must constantly accelerate according to Newton's 2nd law of motion. The way this acceleration reveals itself, the object's speed is constantly increasing.

Since the object is speeding up as it falls, there are a few weird things that happen:

 --  It will fall 2 meters in less than double the time for 1 meter.

 --  It will fall 3 meters in less than triple the time for 1 meter.

 --  It will fall 4 meters in less than quadruple the time for 1 meter, and less than double the time for 2 meters.

 --  It will fall 1 meter near the bottom in less time than 1 meter near the top.

None of the choices exactly answers the question.

Choices ' a ' and ' d ' are false statements.

Choice-b is a true statement, but it isn't a "Yes".

Choice-c  is kind of confused, but is probably the one you should select.

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How much power does it take to lift a 30.0 n box 10.0 m high in 5.00 s, if you must apply a 62n force to lift the box?
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Power is defined as the rate at which the body is doing work:
P=\frac{W}{t}
Work is defined as displacement done by the force times that displacement:
W=F\cdot h
We know that we need 62N to move the box, so when we apply this force along the path of 10m we have done:
W=62N\cdot10m=620J
of work.
Now we just divide that by 5s to get how much power is required:
P=\frac{620J}{5s}=124W
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Explanation:

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6 0
3 years ago
What average force is needed to accelerate a 7.00-gram pellet from rest to 155 m/s over a distance of 0.600 m along the barrel o
leonid [27]

Answer: The force needed is 140.22 Newtons.

Explanation:

The key assumption in this problem is that the acceleration is constant along the path of the barrel bringing the pellet from velocity 0 to 155 m/s. This means the velocity is linearly increasing in time.

The force exerted on the pellet is

F = m a

In order to calculate the acceleration, given the displacement d,  

d = \frac{1}{2}at^2\implies a=\frac{2d}{t^2}

we will need to determine the time t it took for the pellet to make the distance through the barrel of 0.6m. That time can be determined using the average velocity of the pellet while traveling through the barrel. Since the velocity is a linear function of time, as mentioned above, the average is easy to calculate as:

\overline{v}=\frac{1}{2}(v_{end}-v_{start})=\frac{1}{2}(155-0)\frac{m}{s}=77.5\frac{m}{s}

This value can be used to determine the time for the pellet through the barrel:

t = \frac{d}{\overline{v}}=\frac{0.6m}{77.5\frac{m}{s}}\approx0.00774s

Finally, we can use the above to calculate the force:

F = ma = m\frac{2d}{t^2} = 0.007kg\cdot \frac{2\cdot 0.6 m}{0.00774^2 s^2}\approx 140.22N



8 0
3 years ago
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