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lions [1.4K]
1 year ago
12

What is the ATOMIC NUMBER for an element with 5 protons, 6 neutrons and 2 electrons?

Chemistry
1 answer:
Ronch [10]1 year ago
8 0

The element's Atomic number , which has 5 protons, 6 neutrons, and 2 electrons (the atomic number is the number of protons) =  5

<h3>What in an atomic number?</h3>

the number assigned to a chemical element according to its atomic number in the periodic system, which places the elements in ascending order of the number of protons in their nuclei. As a result, the atomic number is also the number of protons, which in a neutral atom is always equal to the amount of electrons.

<h3>Briefing:</h3>

Protons and neutrons are added to determine an element's mass number. The only number that may change while maintaining the identity of an element is the number of neutrons for that element (because the atomic number is the number of protons).

Mass number = protons + neutrons

<h3>According to the given data;</h3>

Given:

5 protons,

6 neutrons

2 electrons

Atomic number = ?

We know that the Mass number = protons + neutrons:

Mass number = protons + neutrons

Mass number = 5 + 6:

Mass number = 11

The element's Atomic number , which has 5 protons, 6 neutrons, and 2 electrons (the atomic number is the number of protons) =  5.

To know more about Atomic number  visit:

brainly.com/question/16858932

#SPJ10

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The oxidation state of phosphorus is +3 in
IgorC [24]

Answer:

b) Phosphorus acid

Explanation:

To distinguish the type of acid of phosphorus with the oxidation state of +3, we need to be familiar with the chemical formula of each of the compounds:

    Orthophosphoric acid             H₃PO₄

    Phosphorus acid                       H₃PO₃

    Metaphosphoric acid               HPO₃

    Phyrophosphoric acid​               H₄P₂O₇

Now that we know the formula of the given compounds, the algebraic sum of all the oxidation numbers of all atoms in a neutral compound is zero:

Only phosphorus acid yielded an oxidation state of +3 for phosphorus in the compound.

  H₃PO₃:

   we know the oxidation state of H = +1

                                                          O = -2

         The oxidation state of P is unknown. We can express this as an equation:

                3(+1) + P + 3(-2) = 0

                    3 + P -6 = 0

                          P-3 = 0

                          P = +3

6 0
3 years ago
What is the transfer of electrons in Al + Cl = AlCl3
otez555 [7]

Answer:

3 e⁻ transfer has occurred.

Explanation

This is a redox reaction.

  • Oxidation (loss of electrons or increase in the oxidation state of entity)
  • Reduction (gain of electrons or decrease in the oxidation state of the entity)
  • An element undergoes oxidation or reduction in order to achieve a stable configuration. It can be an octet or duplet configuration. An octet configuration is that of outer shell configuration of noble gas.
  • [Ne]= (1s²) (2s² 2p⁶)

A combination of both the reactions( Half-reactions) leads to a redox reaction.

Let us look at initial configurations of Al and Cl

[Al]= 1s² 2s² 2p⁶ 3s² 3p¹

[Cl]= 1s² 2s² 2p⁶ 3s² 3p⁵

Hence, Al can lose 3 electrons to achieve octet config.

and, Cl can gain 1e to achieve nearest noble gas config. [Ar]

This reaction can be rewritten, by clearly mentioning the oxidation states of all the entities involved.

Al⁰ + Cl⁰ → (Al⁺³)(Cl⁻)₃

Here, Aluminum is undergoing an oxidation(i.e loss of electrons) from: 0→(+3)

Chlorine undergoes a reduction half reaction (i.e gain of electrons) from: 0→(-1). There are 3 such chlorine atoms, hence 3 e⁻ transfer has occurred.

3 0
3 years ago
Explain how water is able to control fire.<br><br><br>Answer ASAP<br><br>Plzz​
klemol [59]

Answer: Fire requires oxygen to burn. Water "smothers" fire and prevents it from acquiring more oxygen. Fire also requires heat, which cool water may prevent/remove.

7 0
3 years ago
Read 2 more answers
Two closed vessels contain chlorine gas at the same conditions of temperature and
wariber [46]

Answer:12 mol

Explanation: both vessels are at the same temp and pressure (and the pressure is low and/or the temperature high).

6.7mol per 1.3L = 6.7/1.3 mol/L

so in 2.33L = 6.7*2.33/1.3 = 12 mol

8 0
3 years ago
A compound is found to contain 73.23% xenon name 26.77% oxygen by mass. What is the empirical formula for this compound ?
Luba_88 [7]

The empirical formula is XeO₃.

<u>Explanation:</u>

Assume 100 g of the compound is present. This changes the percents to grams:

Given mass in g:

Xenon = 73.23 g

Oxygen = 26.77 g

We have to convert it to moles.

Xe = 73.23/   131.293 = 0.56 moles

O = 26.77/ 16 = 1.67 moles

Divide by the lowest value, seeking the smallest whole-number ratio:

Xe = 0.56/ 0.56 = 1

O = 1.67/ 0.56 = 2.9 ≈3

So the empirical formula is XeO₃.

6 0
3 years ago
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