Answer:
Explanation:
HA(aq)+H2O(l)⟺H3O+(aq)+A−(aq)(1)
you need to solve for the Ka value. To do that you use
Ka=[H3O+][A−][HA](2)
Another necessary value is the pKa value, and that is obtained through pKa=−logKa
The procedure is very similar for weak bases. The general equation of a weak base is
BOH⟺B++OH−(3)
Solving for the Kbvalue is the same as the Ka value. You use the formula
Kb=[B+][OH−][BOH](4)
The pKb value is found through pKb=−logKb
The Kw value is found withKw=[H3O+][OH−].
Kw=1.0×10−14(5)
Answer:
636 balloons
Explanation:
If we assume that helium gas follows an ideal gas behaviour, we can use the ideal gas law to solve this problem as follows:
- We consider two different states, the initial given by the conditions of the problem statement and the final, when the tank reaches atmospheric pressure and it's no longer able to fill balloons:
- To find out what would be this volume 2, we use the Boyle's Law:
- Now we find the available volume to fill the balloons by substracting both, volume 2 and volume 1:
- Finally, we determine the quantity of ballons by dividing that available volume between the volume of each ballon:
Answer: voltage drops in each resistor ΔU= RI
Explanation: if lamps or other resistor which cause load are in series in
Electric circuit, current I passing circuit is same. Voltage decreases
In every resistor
One mole of Fe(NO3)3, or iron(III) nitrate, has three moles of nitrate molecules, which have three moles of oxygen atoms each. We can show this mathematically:
1 mole Fe(NO3)3 * (3 moles NO3)/(1 mole Fe(NO3)3) = 3 moles NO3
3 moles NO3 * (3 moles Oxygen)/(1 mole NO3) = 9 moles Oxygen
9 moles of Oxygen in one mole Fe(NO3)3
Answer:
Determination to succeed.
Explanation:
