It would have to be carbon dioxide, the only gas listed. For gases, 1 mole of particles occupies 22.4 L of volume at STP.
You can never say that any substance is a liquid, a solid, or a gas. Every substance you name can be all of those, depending on the TEMPERATURE.
At standard pressure . . .
-- Iodine is solid below 113.7°C, and gas above 184°C .
-- Bromine is solid below -7.2°C, and gas above 58.8°C .
-- "Room temperature" is considered to be the range from 20°C to 23.5°C.
-- Iodine is solid in that range.
-- Bromine one of only two elements that are known to be liquids AT
ROOM TEMPERATURE. The other one is mercury ... a metal.
Answer:
Ethanol
Explanation:
Given parameters:
Mass of the object = 7g
volume of the object = 10mL
Unknown:
The kind of substance it is = ?
Solution:
Since from the parameters, we can determine the density of the object. Density is an intensive property of substances.
So, we simply find the density and check a density table for the type of substance it is.
Density is the mass per unit volume.
Density =
Let us take the volume to cm³;
10mL = 10cm³
Density =
= 0.7g/cm³
This is most likely ethanol
Answer:
predators are controlling the population of the species who are below them in the food pyramid . Also if the population of the preys decrease it will alternatively reduce the predator population .therefore the predator prey relationship balance an eco system.
The equilibrium constant(Kc) is equal to the concentration of the products over the concentration of the reactants, and each coefficient of the compound in an equilibrium state
<h3>Further explanation</h3>
The equilibrium constant or Kc is the value of the concentration product in the equilibrium state of the substance in the right segment divided by the product of the substance in the left section, each of which has a reaction coefficient raised
solid (s) and liquid (l) have no concentration, so these two phases are not involved in the equilibrium constant KC (given the value = 1).
The equilibrium constant based on concentration (Kc) in a reaction
pA + qB -----> mC + nD
![\tt Kc=\dfrac{[C]^m[D]^n}{[A]^p[B]^q}](https://tex.z-dn.net/?f=%5Ctt%20Kc%3D%5Cdfrac%7B%5BC%5D%5Em%5BD%5D%5En%7D%7B%5BA%5D%5Ep%5BB%5D%5Eq%7D)
1. N2(g) + O2(g) ⇌ 2NO(g)
![\tt Kc=\dfrac{[NO]^2}{[N_2][O_2]}](https://tex.z-dn.net/?f=%5Ctt%20Kc%3D%5Cdfrac%7B%5BNO%5D%5E2%7D%7B%5BN_2%5D%5BO_2%5D%7D)
2. N2(g) + 3H2(g) ⇌ 2NH3(g)
![\tt Kc=\dfrac{[NH_3]^2}{[N_2][H_2]^3}](https://tex.z-dn.net/?f=%5Ctt%20Kc%3D%5Cdfrac%7B%5BNH_3%5D%5E2%7D%7B%5BN_2%5D%5BH_2%5D%5E3%7D)
3. 2SO2(g) + O2(g) ⇌ 3SO3(g)
![\tt Kc=\dfrac{[SO_3]^3}{[SO_2]^2[O_2]}](https://tex.z-dn.net/?f=%5Ctt%20Kc%3D%5Cdfrac%7B%5BSO_3%5D%5E3%7D%7B%5BSO_2%5D%5E2%5BO_2%5D%7D)
4. 2Fe(S) + 4H2O(g) ⇌Fe3O4(s) +4H2(g)
![\tt Kc=\dfrac{[H_2]^4}{[H_2O]^4}](https://tex.z-dn.net/?f=%5Ctt%20Kc%3D%5Cdfrac%7B%5BH_2%5D%5E4%7D%7B%5BH_2O%5D%5E4%7D)