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Deffense [45]
1 year ago
7

1. if the barometer reading is recorded to be higher than the actual value. what effect does this error have on the reported val

ue of the molar mass of the compound? briefly explain (too high, too low, unchanged)
Chemistry
1 answer:
user100 [1]1 year ago
5 0

If the barometer reading is too high, the molar mass of the compound will be too low. If the barometer reading is too low, the molar mass of the compound will be too high.

The molar mass of the compound will be reported as higher than the actual value. This is because the barometer is used to calculate the pressure of the gas, and the pressure is used to calculate the molar mass. If the pressure is too high, the molar mass will be too low.

A barometer is an instrument that is used to measure the pressure of a gas. The pressure of a gas is the force that the gas exerts on a surface. The pressure of a gas is usually expressed in units of atmospheres.The molar mass of a substance is the mass of one mole of the substance. The molar mass of a substance is usually expressed in grams per mole. Hence if the barometer reading is recorded to be higher than the actual value, the reported value of the molar mass of the compound will be too low.

Learn more about pressure at : brainly.com/question/12971272

#SPJ4

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3 years ago
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Consider the following balanced reaction. How many grams of water are required to form 75.9 g of HNO3? Assume that there is exce
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Answer:

The answer is "10.84 g".

Explanation:

The formula for calculating the number for moles:

\text{Number of moles }= \frac{\ Mass}{ \ molar \ mass }

In the given acid nitric:

Owing to the nitric acid mass = 75.9 g

Nitric acid molar weight= 63\  \frac{g}{mol}

If they put values above the formula, they receive:

\text{moles in nitric acid} = \frac{75.9}{63}

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In the given chemical equation:

3 NO_2 \ (g) + H_2O \ (l) \longroghtarrow 2 HNO_3 \ (aq) + NO\ (g)

In this reaction, 2 mols of nitric acid are produced by 1 mole of water.

So, 1.204 moles of nitric acid will be produced:

= \frac{1}{2} \times 1.204

=0.602\ \ \text{mol of water}.

We are now using Equation 1 in determining the quantity of water:

Water moles = 0.602\  mol

Water weight molar = 18.02 \ \frac{g}{mol}

\to 0.602 = \frac{\text{mass of mols}}{ 18.02}\\\\\to \text{mass of mols} = 0.602 \times 18.02\\\\

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Question 6 (4 points)
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Answer:

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Explanation:

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Answer:

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Explanation:

Reversible reactions have a bit practical interest, but in some cases the technological benefit or profitability of production requires a shift in the equilibrium of a reversible reaction.

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When the temperature rises, the equilibrium shifts towards the endothermic reaction, and when the temperature decreases, towards the exothermic reaction and the reaction given above is the exothermic.

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