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Tatiana [17]
3 years ago
9

A solution is prepared by dissolving 15.0 g of NH3 in 250 g of water. The density of the resulting solution is 0.974 g/mL. The m

ole fraction of NH3 in the solution is _____.A) 16.8B) 0.940C) 0.0597D) 0.922E) 0.0640
Chemistry
1 answer:
inn [45]3 years ago
4 0

Answer:

Mole fraction of NH_{3} in solution is 0.0597.

Explanation:

Molar mass of NH_{3} = 17.031 g/mol

Molar mass of H_{2}O = 18.015 g/mol

No. of moles = (mass)/(molar mass)

So, 15.0 g of NH_{3} = \frac{15.0}{17.031} moles of NH_{3} = 0.8807 moles of NH_{3}

      250 g of H_{2}O = \frac{250}{18.015} moles of H_{2}O = 13.88 moles of H_{2}O

So, Mole fraction of NH_{3} in the solution = (no.of moles of NH_{3} )/(total no. of moles) = \frac{0.8807}{0.8807+13.88} = 0.0597

Hence, mole fraction of NH_{3} in solution is 0.0597.

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