The molarity of the resulting solution obtained by mixing 658 mL of 0.250 M HCl solution with 325 mL of 0.600 M HCl solution is 0.366 M
We'll begin by calculating the number of mole of HCl in each solution. This can be obtained as follow:
<h3>For solution 1:</h3>
Volume = 658 mL = 658 / 1000 = 0.658 L
Molarity = 0.250 M
<h3>Mole of HCl =?</h3>
Mole = Molarity x Volume
Mole of HCl = 0.250 × 0.658
<h3>Mole of HCl = 0.1645 mole</h3>
<h3>For solution 2:</h3>
Volume = 325 mL = 325 / 1000 = 0.325 L
Molarity = 0.6 M
<h3>Mole of HCl =?</h3>
Mole = Molarity x Volume
Mole of HCl = 0.6 × 0.325
<h3>Mole of HCl = 0.195 mole</h3>
- Next, we shall determine the total mole of HCl in the final solution. This can be obtained as follow:
Mole of HCl in solution 1 = 0.1645 mole
Mole of HCl in solution 2 = 0.195 mole
Total mole = 0.1645 + 0.195
<h3>Total mole = 0.3595 mole</h3>
- Next, we shall determine the total volume of the final solution.
Volume of solution 1 = 0.658 L
Volume of solution 2 = 0.325 L
Total Volume = 0.658 + 0.325
<h3>Total Volume = 0.983 L</h3>
- Finally, we shall determine the molarity of the resulting solution.
Total mole = 0.3595 mole
Total Volume = 0.983 L
<h3>Molarity =?</h3>
Molarity = mole / Volume
Molarity = 0.3595 / 0.983
<h3>Molarity = 0.366 M</h3>
Therefore, the molarity of the resulting solution is 0.366 M
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