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kenny6666 [7]
1 year ago
15

a simple machine that combines two inclined planes and is used to split objects is called a . group of answer choices

Physics
1 answer:
Semmy [17]1 year ago
5 0

Answer:

The answer is a wedge.

Explanation:

The wedge is a combination of two inclined planes. It is used to separate bodies which are held together by large forces, e.g, splitting timber

M.A.= slant height of wedge/thickness of wedge.

Hence a long thin wedge has a higher mechanical advantage than a short thick one; or the smaller the angle theta between the slant heights, the greater the mechanical advantage.

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All of the following would be questions that could be scientifically investigated except A.
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What is the kinetic energy of a 1200 kg object that is moving at a speed of 24m/s?
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Here, K.E. = 1/2 * mv²

So, K.E. = 1/2 * (1200) * (24)²

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3 years ago
Nerve impulses in a human body travel at a speed of about 100 m/s. Suppose a person accidentally steps barefoot on a pebble. Abo
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Answer:

The time required by the impulse to travel from foot to brain equals 0.019 seconds

Explanation:

For uniform motion the distance, speed, time are related by the equation

Distance=Speed\times time

In our case since the person is 1.90 meters tall so the nerve impulse will have to cover a distance of 1.90 meters at a speed of 100 m/s.

Hence the time required for the impulse to travel from foot to the brain can be calculated as

time=\frac{Distance}{speed}\\\\\therefore time=\frac{1.90m}{100m/s}=0.019seconds

4 0
3 years ago
Suppose that a 102.5 kg football player running at 8.5 m/s catches a 0.47 kg ball moving at a speed of 22.5 m/s with his feet of
nadya68 [22]

Answer:

a) v=8.564\ m.s^{-1}

b) \Delta KE=45.76\ J

c) v=8.358\ m.s^{-1}

d) \Delta KE=225.24\ J

Explanation:

Given:

mass of the player, m_p=102.5\ kg

mass of the ball, m_b=0.47\ kg

initial velocity of the player, v_p=8.5\ m.s^{-1}

initial velocity of the ball, v_b=22.5\ m.s^{-1}

a)

<u>Case:</u> When the player and the ball are moving in the same direction.

m_t.v=m_p.v_p+m_b.v_b

where:

m_t=total mass after the player catches the ball

v = final velocity of the system

v=\frac{102.5\times 8.5+0.47\times 22.5}{(102.5+0.47)}

v=8.564\ m.s^{-1}

b)

Initial kinetic energy of the system:

KE_i=\frac{1}{2} [m_p.v_p^2+m_b.v_b^2]

KE_i=\frac{1}{2} [102.5\times 8.5^2+0.47\times 22.5^2]

KE_i=3821.78\ J

Final kinetic energy of the system:

KE_f=\frac{1}{2} m_t.v^2

KE_f=\frac{1}{2}\times 102.97\times 8.564^2

KE_f=3776.02\ J

∴Change in kinetic energy

\Delta KE=KE_i-KE_f

\Delta KE=3821.78-3776.02

\Delta KE=45.76\ J

c)

<u>Case:</u> When the player and the ball are moving in the opposite direction.

m_t.v=m_p.v_p-m_b.v_b

v=\frac{102.5\times 8.5-0.47\times 22.5}{(102.5+0.47)}

v=8.358\ m.s^{-1}

d)

Final kinetic energy in this case:

KE_f=\frac{1}{2} m_t.v^2

KE_f=0.5\times 102.97\times 8.358^2

KE_f=3596.54\ J

∴Change in kinetic energy:

\Delta KE=KE_i-KE_f

\Delta KE=3821.78-3596.54

\Delta KE=225.24\ J

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True,
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