Answer:
C. Equals
Explanation:
Law of reflection Equals the angle of incidence
Answer:
(A) 140 j/sec (b) 1.26 K
Explanation:
We have given the heat heat flowing into the refrigerator = 40 J/sec
Work done = 40 W
(a) So the heat discharged from the refrigerator ![=heat\ flowing\ in\ refrigerator+work\ done=40+100=140j/sec](https://tex.z-dn.net/?f=%3Dheat%5C%20flowing%5C%20in%5C%20refrigerator%2Bwork%5C%20done%3D40%2B100%3D140j%2Fsec)
(b) Total heat absorbed =140 j/sec ![=140\times 3600=504000j/hour](https://tex.z-dn.net/?f=%3D140%5Ctimes%203600%3D504000j%2Fhour)
Let the temperature be ![\Delta T](https://tex.z-dn.net/?f=%5CDelta%20T)
Heat absorbed per hour =504000 ![[tex]=400\times 10^3\times \Delta T](https://tex.z-dn.net/?f=%5Btex%5D%3D400%5Ctimes%2010%5E3%5Ctimes%20%5CDelta%20T)
So ![\Delta T=\frac{504000}{400000}=1.26K](https://tex.z-dn.net/?f=%5CDelta%20T%3D%5Cfrac%7B504000%7D%7B400000%7D%3D1.26K)
Generally, rings form from moons, asteroids, or comets that have disintegrated due to a collision or because they got too close to their planet (Roche Limit). ... Most of the debris, however, will not have enough energy to overcome the planet's gravity and will remain in orbit around the planet.
Explanation:
Given that,
Wavelength of the light, ![\lambda=4170\ A=4170\times 10^{-10}\ m](https://tex.z-dn.net/?f=%5Clambda%3D4170%5C%20A%3D4170%5Ctimes%2010%5E%7B-10%7D%5C%20m)
Work function of sodium, ![W_o=4.41\times 10^{-19}\ J](https://tex.z-dn.net/?f=W_o%3D4.41%5Ctimes%2010%5E%7B-19%7D%5C%20J)
The kinetic energy of the ejected electron in terms of work function is given by :
![KE=h\dfrac{c}{\lambda}-W_o\\\\KE=6.63\times 10^{-34}\times \dfrac{3\times 10^8}{4170\times 10^{-10}}-4.41\times 10^{-19}\\\\KE=3.59\times 10^{-20}\ J](https://tex.z-dn.net/?f=KE%3Dh%5Cdfrac%7Bc%7D%7B%5Clambda%7D-W_o%5C%5C%5C%5CKE%3D6.63%5Ctimes%2010%5E%7B-34%7D%5Ctimes%20%5Cdfrac%7B3%5Ctimes%2010%5E8%7D%7B4170%5Ctimes%2010%5E%7B-10%7D%7D-4.41%5Ctimes%2010%5E%7B-19%7D%5C%5C%5C%5CKE%3D3.59%5Ctimes%2010%5E%7B-20%7D%5C%20J)
The formula of kinetic energy is given by :
![KE=\dfrac{1}{2}mv^2\\\\v=\sqrt{\dfrac{2KE}{m}} \\\\v=\sqrt{\dfrac{2\times 3.59\times 10^{-20}}{9.1\times 10^{-31}}} \\\\v=2.8\times 10^5\ m/s](https://tex.z-dn.net/?f=KE%3D%5Cdfrac%7B1%7D%7B2%7Dmv%5E2%5C%5C%5C%5Cv%3D%5Csqrt%7B%5Cdfrac%7B2KE%7D%7Bm%7D%7D%20%5C%5C%5C%5Cv%3D%5Csqrt%7B%5Cdfrac%7B2%5Ctimes%203.59%5Ctimes%2010%5E%7B-20%7D%7D%7B9.1%5Ctimes%2010%5E%7B-31%7D%7D%7D%20%5C%5C%5C%5Cv%3D2.8%5Ctimes%2010%5E5%5C%20m%2Fs)
Hence, this is the required solution.
The CORRECT answer would be false. They are different and so therefore the answer is false.
Hope this helped ‼️