Answer:
The combination of oxygen with other substances to produce new chemical products is called <u>Oxidation</u>.
Explanation:
Oxidation reactions are defined as,
In terms of Inorganic chemistry:
(i) <u>Removal of Electrons: </u>
Example: Mg → Mg²⁺ + 2 e⁻
(ii) <u>Addition of Oxygen:</u>
Example: 2 Mg + O₂ → 2 MgO
In terms of Organic chemistry:
(i) <u>Addition of Electrons: </u>
Example: Cl₂ + 2 e⁻ → 2 Cl⁻
(ii) <u>Addition of Hydrogen:</u>
Example: H₂CCH₂ + H₂ → H₃CCH₃
Its either b or c, but i think its b
Equation for oxygen gas molecules
1.5O₂ + 2Al => Al₂O₃
ratio of aluminium to oxygen is
2:1.5
when Al is 7.5
O₂ is 3.75
Answer:
The question is incomplete and confusing.
- In the complete ionic equation you write all the ions that are formed. Those are: Pb²⁺, NO₃⁻, K⁺, and I⁻. They all are present in the complete ionic equation.
- In the net ionic equation, the spectator ions do not appear. They are: NO₃⁻ and K⁺. They would not be present in the net ionic equation, but they do in the complete ionic equation.
See below the details.
Explanation:
Which compound will not form ions?
<u />
<u>1. Write the balanced molecular equation:</u>
- Pb(NO₃)₂(aq) + 2KI(aq) → PbI₂(s) + 2KNO₃(aq)
<u />
<u>2. Write the ionizations for the ionic aqueous compounds:</u>
<u />
- Pb(NO₃)₂(aq) → Pb⁺²(aq) + 2NO₃⁻(aq)
- 2KI(aq) → 2K⁺(aq) + 2I⁻(aq)
- 2KNO₃(aq) → 2K⁺(aq) + 2NO₃⁻(aq)
<u />
<u>3. Write the complete ionic equation:</u>
Pb⁺²(aq) + 2NO₃⁻(aq) + 2K⁺(aq) + 2I⁻(aq) → PbI₂(s) + 2K⁺(aq) + 2NO₃⁻(aq)
Hence, since PbI₂(s) does not ionize, but stays in solid form, it will not form ions.
All, Pb⁺², NO₃⁻, K⁺, and I⁻ will be present in the total ionic equation.
It is in the net ionic equation that the spectator ions are removed. Those, are NO₃⁻ and K⁺, because they are on both sides of the complete ionic equation.
