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Reil [10]
1 year ago
13

Which list of fractions is in order from smallest to largest A. 3/4 3/5 3/10 3/12. B. 5/3 3/4 3/12 3/10 C. 3/10 3/5 3/4 3/12. D.

3/12 3/10 3/5 3/4
Mathematics
1 answer:
Pepsi [2]1 year ago
5 0

A. 3/4 = 0.75 3/5 = 0.6 3/10 = 0.3 3/12 = 0.25

Right order

3/12 < 3/10 < 3/5 < 3/4

The right answer is letter D.

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Kent multiplies both sides of the equation below by an expression.
Korolek [52]
The steps below are presented in order to arrive to the value of k of the given equation. 
First, multiply both sides of the equation by the variable k since the left-hand side of the equation has it in the denominator. This will be,  
            (k + 12/ k)(k) = 8(k)

Then, we simplify,
             k + 12 = 8k
We then, subtract 8k to both sides of the equation,
           k - 8k + 12 = 8k - 8k

Simplifying,
                  -7k + 12 = 0

Then, subtract 12 from both sides of the equation and divide both sides by -7. This will us the final answer of,                  
                     k = 12/7
8 0
4 years ago
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The diameter of a regulation socver ball is about 8 3/5 inches. This number was graphed on a number line. Which point could be p
maria [59]

Answer:

A

Step-by-step explanation:

3 0
3 years ago
The sum of two numbers is 67 . the larger number is 5 more than the smaller number. what are the numbers?
Scorpion4ik [409]
Call the numbers x and y. According to the first sentence, x + y = 67. According to the second sentence, x = y + 5. You can combine these two equations to find the values of these variables:

x + y = 67
(y + 5) + y= 67
2y = 62
y = 31

You can use this to find x by plugging in y to either original equation:

x = y + 5
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8 0
3 years ago
Simplify each only using positive exponents:<br> 2x^-3 • 4x^2<br> 2x^4 • 4x^-3<br> 2x^3y^-3 • 2x
erica [24]
<h2>Answer:</h2>

\frac{2}{x}

\frac{x}{2}

\frac{4x^4}{y^3}

<h2>Step-by-step explanation:</h2>

a. 2x^-3 • 4x^2

To solve this using only positive exponents, follow these steps:

i. Rewrite the expression in a clearer form

2x⁻³ . 4x²

ii. The position of the term with negative exponent is changed from denominator to numerator or numerator to denominator depending on its initial position. If it is at the numerator, it is moved to the denominator. If otherwise it is at the denominator, it is moved to the numerator. When this is done, the negative exponent is changed to positive.

In our case, the first term has a negative exponent and it is at the numerator. We therefore move it to the denominator and change the negative exponent to  positive as follows;

\frac{1}{2x^3} . 4x^2

iii. We then solve the result as follows;

\frac{1}{2x^3} . 4x^2 = \frac{2}{x}

Therefore, 2x⁻³ . 4x² = \frac{2}{x}

b. 2x^4 • 4x^-3

i. Rewrite as follows;

2x⁴ . 4x⁻³

ii. The second term has a negative exponent, therefore swap its position and change the negative exponent to a positive one.

2x^4 . \frac{1}{4x^3}

iii. Now solve by cancelling out common terms in the numerator and denominator. So we have;

\frac{x}{2}

Therefore, 2x⁴ . 4x⁻³ = \frac{x}{2}

c. 2x^3y^-3 • 2x

i. Rewrite as follows;

2x³y⁻³ . 2x

ii. Change position of terms with negative exponents;

2x^3.\frac{1}{y^3} .2x

iii. Now solve;

\frac{4x^4}{y^3}

Therefore, 2x³y⁻³ . 2x = \frac{4x^4}{y^3}

8 0
3 years ago
Evaluate . | 6a |- 10 for a = - 7
Ilia_Sergeevich [38]
The answer would be 32. This is because once you input -7 you multiply -7 and 6 and end up with -42 but since it is in absolute value it turns into positive 42. Now it is 42 - 10. At this point all you do is subtract which will get you 32. Hope this helps ; )
8 0
3 years ago
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