Answer:
55.1 g Si.
Explanation:
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In this case, for the given mole-mole relationship, it is possible to set up the following mole ratio as the moles of Si and P are the same:
1 mol Si = 1 mol P.
Next, since one mole of silicon has a mass of 28.09 g and one of phosphorous of 31.0 g, we can set up the following expression for the mass of silicon:
Therefore, the result is 55.1 grams of silicon.
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Metals are lustrous, malleable, ductile, good conductors of heat and electricity. Other properties include: State: Metals are solids at room temperature with the exception of mercury, which is liquid at room temperature
Answer:
The answer to your question is: V1 = 27.8 ml of HCl 18 M
Explanation:
Data
HCl = [18M]
HCl Vol = ?
HCl = [ 2M]
HCl vol = 250 ml
Formula
V₁ C₁ = V₂ C₂
V₁ = V₂ C₂ / C₁
Process (substitution)
V₁ = (250)(2) / 18
V₁ = 500 / 18
V1 = 27.8 ml
Answer: n-Butanol are converted using SN2 and tert-butanol is converted using SN1
Explanation: For the conversion of n-butanol into butyl chloride using Hydrogen Chloride the reaction would follow SN2 mechanism.
SN2 reaction mechanism occurs only in the case of primary substrates as it is a one step mechanism that happens in a concerted manner. It involves backside attack of nucleophile on the substrate such that the nucleophile attacks from the back side and leaving group leaves from the front side.
In this reaction since hydroxy group (OH) is not a good leaving group hence firstly we need to convert it into a good leaving group. When we treat n-butanol with HCl hydroxy group is protonated and now it turns into a good leaving group as it can leave as H₂O.
Cl⁻ here acts as nucleophile and now attacks the primary carbon center from the back side which contains the protonated hydroxy group as a leaving group.
In the case of tertiary butanol the reaction follows SN1 mechanism and it is 2 step mechanism.
In the first step hydroxy group is protonated and as it becomes a good leaving group it leaves and leads to the formation of a stable tertiary carbocation as an intermediate.
In the second step this intermediate carbocation is attacked by the Cl⁻ nucleophile which leads to the formation of tertiary butyl chloride.
Kindly find in attachment the reaction mechanism for both the reactions.
<u>Answer</u>;
Falsfiable
<h3><u>Explanation</u>;</h3>
- <u>Scientific Hypothesis</u> is a proposed set of phenomena that must be testable with evidence from the natural world. If an hypothesis cant be tested then it's not a scientific hypothesis.
- <u>Scientific Theory</u> is a broad explanation for a wide range of phenomena and usually integrate many individual hypothesis. The theory must be testable with evidence to support the theory.
- <u>Scientific Laws</u> on the other hand is a statement based on repeated experimental observations that describes some aspect of the world.
- <em><u>Scientific statement, hypothesis, or theory should have falsifiability or should be falsifiable. Falsifiability refers to the capacity for some proposition, statement, theory or hypothesis to be proven wrong.</u></em>