Answer:
Ununennium, also known as eka-francium or element 119, is the hypothetical chemical element with symbol Uue and atomic number 119. Ununennium and Uue are the temporary systematic IUPAC name and symbol respectively, which are used until the element is discovered, confirmed, and a permanent name is decided upon. In the periodic table of the elements, it is expected to be an s-block element, an alkali metal, and the first element in the eighth period. It is the lightest element that has not yet been synthesized.
Explanation:
In a compund, the proportion must be fixed, unlike mixture. Therefore, if he just combine two elements, there must be excess elements mixed in it.
Second, how did he combined two elements? In order to create a compund, either heat or electricity must be applied.
Therefore, even if he used heat / electricity, he still hasn't got the right proportion, therefore he must have mixed some excess elements into the compund that he thought he made.
Answer:
They are solid (with the exception of mercury, Hg, a liquid).
They are shiny, good conductors of electricity and heat.
They are ductile (they can be drawn into thin wires).
They are malleable (they can be easily hammered into very thin sheets).
If this satisfies you please consider giving me brainliest :)
On one end of the electromagnetic spectrum are radio waves, which have wavelengths billions of times longer than those of visible light. On the other end of the spectrum are gamma rays, with wavelengths billions of times smaller than those of visible light.
Answer:
24.0 g C₃H₈
Explanation:
To find the mass of C₃H₈, you need to (1) convert grams CO/H₂ to moles CO/H₂ (via molar mass), then (2) convert moles CO/H₂ to moles C₃H₈ (via mole-to-mole ratio from reaction coefficients), and then (3) convert moles C₃H₈ to grams C₃H₈ (via molar mass). It is important to arrange the conversions/ratios in a way that allows for the cancellation of units (the desired unit should be in the numerator). The final answer should have 3 sig figs to reflect the sig figs in the given values.
Molar Mass (CO): 12.011 g/mol + 15.998 g/mol
Molar Mass (CO): 28.009 g/mol
Molar Mass (H₂): 2(1.008 g/mol)
Molar Mass (H₂): 2.016 g/mol
Molar Mass (C₃H₈): 3(12.011 g/mol) + 8(1.008 g/mol)
Molar Mass (C₃H₈): 44.097 g/mol
3 CO + 7 H₂ ----> 1 C₃H₈ + 3 H₂O
^ ^ ^
45.8 g CO 1 mole 1 mole C₃H₈ 44.097 g
----------------- x ------------------ x -------------------- x ------------------ =
28.009 g 3 moles CO 1 mole
= 24.0 g C₃H₈
87.3 g H₂ 1 mole 1 mole C₃H₈ 44.097 g
---------------- x --------------- x --------------------- x ----------------- =
2.016 g 7 moles H₂ 1 mole
= 273 g C₃H₈
It was necessary to find the mass of the products from both of the reactants because you did not know which one was the limiting reagent. The limiting reagent is the reactant which is completely used up first. Because CO produced the smaller amount of product, it must be the limiting reagent. Therefore, the actual amount of C₃H₈ produced is 24.0 grams.
